题解 | #翻转单词序列#
翻转单词序列
https://www.nowcoder.com/practice/3194a4f4cf814f63919d0790578d51f3
方法一:借助栈的先入后出反转字符串(栈+StringBuilder+String[])
public String ReverseSentence(String str) {
//if(str==null)//这种字符串判空方式会报错
//if(str.isEmpty())//字符串判空0
//if(str.trim().equals(""))//字符串判空1
if(str.length()<=0)return str;//字符串判空2
String[] sArr = str.trim().split(" ");//分割字符串用数组接收
Deque<String> stk = new LinkedList<>();//用Deque代替Stack
for(int i =0;i<sArr.length;i++){
stk.push(sArr[i]);
}
StringBuilder sb = new StringBuilder();
while(!stk.isEmpty()){//栈的判空
String s = stk.pop();
sb.append(s+" ");
}
return sb.toString().trim();
}
方法二:无需栈,字符串数组遍历时直接倒序加入StringBuilder
public String ReverseSentence(String str) {
//if(str==null)//这种字符串判空方式会报错
//if(str.isEmpty())//字符串判空0
//if(str.trim().equals(""))//字符串判空1
if(str.length()<=0)return str;//字符串判空2
String[] sArr = str.trim().split(" ");
StringBuilder sb = new StringBuilder();
for(int i =0;i<sArr.length;i++){
sb.append(sArr[sArr.length-1-i]);//无需栈,直接倒序加入StringBuilder
sb.append(" ");
}
return sb.toString().trim();
}
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