题解 | #输出单向链表中倒数第k个结点#
输出单向链表中倒数第k个结点
http://www.nowcoder.com/practice/54404a78aec1435a81150f15f899417d
package main import( "fmt" ) func main(){ for{ var num int _,e := fmt.Scanf("%d",&num) if e!=nil{ break } slice := make([]int,num) for i:=0; i<num; i++{ fmt.Scanf("%d",&slice[i]) } var index int fmt.Scanf("%d",&index) if index>0{ fmt.Println(slice[num-index]) }else{ fmt.Println(0) } } }