题解 | #字符串分隔#

import java.util.Scanner;

public class Main { public static void main(String[] args) { Scanner input = new Scanner(System.in); String str =input.nextLine(); int n = str.length(); // System.out.println(n);

    //判断字符串有几个8的倍数
    int beishu=n/8;
    //判断是否有余数
    int yushu =n%8;
    //减去余数应添加的0个数
    int add0=8-yushu;

    if (yushu!=0&&str.length()<8){       //字符串大小小于8
        yushu=8-str.length();
        add0=8-str.length();
        String str2[] = new String[1];
        str2[0]=str;
        for (int i = 0; i <add0 ; i++) {
            str2[0]=str2[0]+"0";
        }
        System.out.println(str2[0]);

    }else if (yushu==0){               //字符串大小为8的倍数
        String str2[]= new String[beishu];
        for (int i = 0; i <str2.length ; i++) {
            str2[i]="";
        }
        for (int i = 0; i <str2.length; i++) {
            for (int j = i*8; j <i*8+8; j++) {
                str2[i]=str2[i]+str.charAt(j);
            }
        }
        for (int i = 0; i <str2.length ; i++) {
            System.out.println(str2[i]);
        }

    }else {                            //字符串大于8且大小不为8的倍数
        String str2[]= new String[beishu+1];
        for (int i = 0; i <str2.length ; i++) {
            str2[i]="";
        }
        for (int i = 0; i <str2.length-1; i++) {
            for (int j = i*8; j <i*8+8; j++)
                    str2[i] = str2[i] + str.charAt(j);
        }
         //补充剩下的字符
        for (int i = 8*beishu; i <str.length(); i++) {
            str2[str2.length-1]=str2[str2.length-1]+str.charAt(i);
        }
        //添加0
        for (int i = 0; i <add0 ; i++) {
            str2[str2.length-1]=str2[str2.length-1]+"0";
        }

        for (int i = 0; i <str2.length ; i++) {
            System.out.println(str2[i]);
        }

    }




}

}