题解 | #简单错误记录#
简单错误记录
http://www.nowcoder.com/practice/2baa6aba39214d6ea91a2e03dff3fbeb
ls1 = [] dic = {} while True: try: s1 = input() n = s1.rfind('\') #存在转义字符，因此\为\ s2 = s1[n+1:] msg = s2.split(' ') s3 = ' '.join([msg[0][-16:], msg[1]]) if s3 not in dic.keys(): ls1.append(s3) dic[s3] = 1 else: dic[s3] += 1 except: break for item in ls1[-8:]: print(item, dic[item])
