题解 | #牛牛的金币#
牛牛的金币
http://www.nowcoder.com/practice/35d8e3e569dc49f2a1018d1dc9186998
#include<stdio.h>
int main()
{
float x = 0;
float y = 0;
float x1 = 0;
float y1 = 0;
char c = 0;
scanf("%f %f",&x,&y);
scanf("%f %f",&x1,&y1);
if(x1-x > 0)
c = 'r';
else if(x1-x < 0)
c = 'l';
else if(y1- y >0)
c = 'u';
else if(y1-y < 0)
c = 'd';
printf("%c\n",c);
return 0;
}
