题解 | #二叉树的后序遍历#
二叉树的后序遍历
http://www.nowcoder.com/practice/1291064f4d5d4bdeaefbf0dd47d78541
import java.util.*;
/*
* public class TreeNode {
* int val = 0;
* TreeNode left = null;
* TreeNode right = null;
* public TreeNode(int val) {
* this.val = val;
* }
* }
*/
public class Solution {
/**
* 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
*
*
* @param root TreeNode类
* @return int整型一维数组
*/
List<Integer> list = new ArrayList<>();
public int[] postorderTraversal (TreeNode root) {
// write code here
postorder(root);
int[] ans = new int[list.size()];
int k = 0;
for(int num : list){
ans[k++] = num;
}
return ans;
if(root == null){
return ;
}
postorder(root.left);
postorder(root.right);
list.add(root.val);
}
}
/*
* public class TreeNode {
* int val = 0;
* TreeNode left = null;
* TreeNode right = null;
* public TreeNode(int val) {
* this.val = val;
* }
* }
*/
public class Solution {
/**
* 代码中的类名、方法名、参数名已经指定,请勿修改,直接返回方法规定的值即可
*
*
* @param root TreeNode类
* @return int整型一维数组
*/
List<Integer> list = new ArrayList<>();
public int[] postorderTraversal (TreeNode root) {
// write code here
postorder(root);
int[] ans = new int[list.size()];
int k = 0;
for(int num : list){
ans[k++] = num;
}
return ans;
}
//后序遍历
public void postorder(TreeNode root){if(root == null){
return ;
}
postorder(root.left);
postorder(root.right);
list.add(root.val);
}
}