题解 | #记负均正#

#include<stdio.h>
int main(){
    int n=0,a[2002]={0};
    while(scanf("%d",&n)==1){
            for(int i=0;i<n;i++)
                scanf("%d",&a[i]);
        int count1=0,count2=0;
        float sum=0;
        for(int i=0;i<n;i++){
           if(a[i]<0)
               count1++;
            else if(a[i]>0){
                count2++;
                sum+=a[i];
            }
        }
        float mean;
        if(count2!=0)
        mean=sum/count2;
        else mean=0;
        printf("%d %.1f",count1,mean);
    }
}