网易互娱 AI笔试 三道题 2个半小时 ac情况

求 第二题代码

第三题 0.9 代码 import heapq T=int(input().strip()) for _ in range(T):     n=int(input().strip())     x,y=0,0     graph={(0,0)}     for i in range(n):         a,b=map(int,input().strip().split())         if b==1:             dx=dy=0             if a==0: dx=-1             elif a==1: dx=1             elif a==2: dy=-1             else:dy=1             x,y=x+dx,y+dy             graph.add((x,y))         if i==n-1:             end=(x,y)     stack=[(0,(0,0))]     used={(0,0)}     while stack:         dis,point=heapq.heappop(stack)         if point==end:             print(dis)             break         for dx,dy in ((-1,0),(1,0),(0,-1),(0,1)):             temp=(point[0]+dx,point[1]+dy)             if temp not in used  and  temp in graph:                 used.add(temp)                 heapq.heappush(stack,(dis+1,temp))

售货机AC，绘制屏幕0.5，迷宫没写完，跪求面试机会

第一题 ac代码  n,m = map(int,input().split()) value=list(map(int,input().split())) extre=[ [] for i in range(n)] for _ in range(m):     k=int(input())     res=0     left=right=None     for _ in range(k):         do=list(input().split())         if do[1]=="take":             do[2]=int(do[2])-1             temp=0             if extre[do[2]]==[]:                 temp=value[do[2]]             else:                 temp=extre[do[2]].pop()             if do[0]=="left":                 left=temp             else:                 right=temp         elif do[1]=="keep":             if do[0]=="left":                 res+=left                 left=0             else:                 res+=right                 right=0         else:             do[2] = int(do[2])-1             if do[0]=="left":                 extre[do[2]].append(left)                 left=0             else:                 extre[do[2]].append(right)                 right=0     if left:res+=left     if right:res+=right     print(res)

可以贴代码学习一下吗