题解 | #字符串加解密#
字符串加解密
http://www.nowcoder.com/practice/2aa32b378a024755a3f251e75cbf233a
描述
对输入的字符串进行加解密，并输出。
加密方法为：
当内容是英文字母时则用该英文字母的后一个字母替换，同时字母变换大小写,如字母a时则替换为B；字母Z时则替换为a；
当内容是数字时则把该数字加1，如0替换1，1替换2，9替换0；
其他字符不做变化。
解密方法为加密的逆过程。
数据范围：输入的两个字符串长度满足 1 \le n \le 1000 \1≤n≤1000 ，保证输入的字符串都是只由大小写字母或者数字组成
输入描述：
第一行输入一串要加密的密码
第二行输入一串加过密的密码
输出描述：
第一行输出加密后的字符
第二行输出解密后的字符
def encode():
s = list(input())
for i in range(len(s)):
if s[i].isalpha():
if s[i] == "Z":
s[i] = "a"
elif s[i] == "z":
s[i] = "A"
else:
if s[i].isupper():
s[i] = chr(ord(s[i]) + 1).lower()
else:
s[i] = chr(ord(s[i]) + 1).upper()
if s[i].isdigit():
if s[i] == "9":
s[i] = "0"
else:
s[i] = str(int(s[i]) + 1)
return "".join(s)
def decode():
s = list(input())
for i in range(len(s)):
if s[i].isalpha():
if s[i] == "a":
s[i] = "Z"
elif s[i] == "A":
s[i] = "z"
else:
if s[i].isupper():
s[i] = chr(ord(s[i]) - 1).lower()
else:
s[i] = chr(ord(s[i]) - 1).upper()
elif s[i].isdigit():
if s[i] == "0":
s[i] = "9"
else:
s[i] = str(int(s[i]) -1)
return "".join(s)
while True:
try:
ret = encode()
ret1 = decode()
print(ret)
print(ret1)
except:
break
s = list(input())
for i in range(len(s)):
if s[i].isalpha():
if s[i] == "Z":
s[i] = "a"
elif s[i] == "z":
s[i] = "A"
else:
if s[i].isupper():
s[i] = chr(ord(s[i]) + 1).lower()
else:
s[i] = chr(ord(s[i]) + 1).upper()
if s[i].isdigit():
if s[i] == "9":
s[i] = "0"
else:
s[i] = str(int(s[i]) + 1)
return "".join(s)
def decode():
s = list(input())
for i in range(len(s)):
if s[i].isalpha():
if s[i] == "a":
s[i] = "Z"
elif s[i] == "A":
s[i] = "z"
else:
if s[i].isupper():
s[i] = chr(ord(s[i]) - 1).lower()
else:
s[i] = chr(ord(s[i]) - 1).upper()
elif s[i].isdigit():
if s[i] == "0":
s[i] = "9"
else:
s[i] = str(int(s[i]) -1)
return "".join(s)
while True:
try:
ret = encode()
ret1 = decode()
print(ret)
print(ret1)
except:
break
