题解 | #在行列都排好序的矩阵中找指定的数#
第一个只出现一次的字符
http://www.nowcoder.com/practice/1c82e8cf713b4bbeb2a5b31cf5b0417c
class Solution:
def FirstNotRepeatingChar(self , str: str) -> int:
# write code here
for i in str:
if str.count(i)==1:
return str.index(i)
return -1
