题解 |CPP58 编写函数实现字符串翻转（引用方式）

#include #include using namespace std;

int main() {

int letter = 0;
int digit = 0;
int space = 0;
int other = 0;

char buf[1024] = {0};
cin.getline(buf, sizeof(buf));

for(int i=0;i<strlen(buf);i++){
    if(buf[i]>='0'&&buf[i]<='9'){
        digit++;
    }else if((buf[i]>='A'&&buf[i]<='Z')||(buf[i]>='a'&&buf[i]<='z')){
        letter++;
    }else if(buf[i]==' '){
        space++;
    }else{
        other++;
    }
}
// write your code here......


cout << "letter:" << letter << " digit:" << digit << " space:" << space << " other:" << other << endl;

return 0;

}