题解 | #简单密码#
简单密码
http://www.nowcoder.com/practice/7960b5038a2142a18e27e4c733855dac
#include <stdio.h>
#include <string.h>
int main(void)
{
char input[1000];
char output[1000] = "\0";
int Nnum = 0,Enum = 0,Knum = 0,Onum = 0;
gets(input);
{
for(int i=0;i<strlen(input);i++)
{
if(input[i] >= 'A' && input[i] <= 'Z')//大写
{
if(input[i] == 'Z')
output[i] = 'a';
else
output[i] = input[i] + 32 + 1;//转换为小写
}
else if(input[i] >= 'a' && input[i] <= 'z')//小写
{
if(input[i]>='a' && input[i]<='c')
output[i]='2';
else if(input[i]>='d' && input[i]<='f')
output[i]='3';
else if(input[i]>='g' && input[i]<='i')
output[i]='4';
else if(input[i]>='j' && input[i]<='l')
output[i]='5';
else if(input[i]>='m' && input[i]<='o')
output[i]='6';
else if(input[i]>='p' && input[i]<='s')
output[i]='7';
else if(input[i]>='t' && input[i]<='v')
output[i]='8';
else if(input[i]>='w' && input[i]<='z')
output[i]='9';
}
else//数字
output[i] = input[i];
}
printf("%s\n",output);
return 0;
}
}
