题解 | #百钱买百鸡问题#
尼科彻斯定理
http://www.nowcoder.com/practice/dbace3a5b3c4480e86ee3277f3fe1e85
#9命，调了好久终于把运行时间调到规定内了🤣
def nk(count,n,m):
if sum(count) == n and len(count) == m:
print(str(count).replace("[","").replace(",", "+").replace("]","").replace(" ",""))
return True
while True:
try:
m = int(input())
n = m * m * m #n是m的立方
count = []
flag = 0
i = 0
while flag ==0:
for j in range(i,i+2*m+1,2):#遍历j往后的m个奇数，若总和为n则输出
count.append(j)
if (nk(count,n,m)):
flag = 1
i += 1
count = []
except:
break
投递京东数科等公司8个岗位 >