题解 | #求int型正整数在内存中存储时1的个数#
方法1：循环运算
num = int(input())
count = 0
while num > 1:
if num % 2 == 1:
count += 1
num = num // 2
if num % 2 == 1:
count += 1
print(count)
方法2：位移运算：
num = int(input())
counts = 0
while num !=0:
if num % 2 == 1:
counts = counts+1
num = num >> 1
print(counts)
