题解 | #连续子数组的最大和#
连续子数组的最大和
http://www.nowcoder.com/practice/459bd355da1549fa8a49e350bf3df484
public class Solution {
public int FindGreatestSumOfSubArray(int[] array) {
//dp[i]:以i结尾的连续子数组最大和
int[] dp = new int[array.length];
dp[0] = array[0];
int maxSum = array[0];
for(int i = 1; i < dp.length; i++){
if(dp[i-1] < 0){
dp[i] = array[i];
}else{
dp[i] = dp[i-1]+array[i];
}
maxSum = Math.max(maxSum, dp[i]);
}
return maxSum;
}
}
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