题解 | #连续子数组的最大和#
连续子数组的最大和
http://www.nowcoder.com/practice/459bd355da1549fa8a49e350bf3df484
public class Solution { public int FindGreatestSumOfSubArray(int[] array) { //dp[i]:以i结尾的连续子数组最大和 int[] dp = new int[array.length]; dp[0] = array[0]; int maxSum = array[0]; for(int i = 1; i < dp.length; i++){ if(dp[i-1] < 0){ dp[i] = array[i]; }else{ dp[i] = dp[i-1]+array[i]; } maxSum = Math.max(maxSum, dp[i]); } return maxSum; } }