题解 | #获得积分最多的人(三)#

with t1 as (
select user_id,case when type='reduce' then -grade_num
    else grade_num
    end as grade_num
    from grade_info
),
total as(
select a.id,name,sum(grade_num) over(partition by name)as grade_sum
from user a 
left join t1 b 
on a.id=b.user_id
order by grade_sum desc
)
select id,name,grade_sum
from total
where grade_sum in(
select max(grade_sum)
    from total
)
group by id
order by id