题解 | #获得积分最多的人(二)#

with total as(
select a.id,name,sum(grade_num) over(partition by name)as grade_sum
from user a 
left join grade_info b 
on a.id=b.user_id
order by grade_sum desc
)
select id,name,grade_sum
from total
where grade_sum in(
select max(grade_sum)
    from total
)
group by id
order by id