题解 | #将字符串转化为整数#
将字符串转化为整数
http://www.nowcoder.com/practice/44d8c152c38f43a1b10e168018dcc13f
//假设已知随即凌乱字符
String a = "1n21ewmnd22 asmnciushvla*/-*/!@#$%^&* ()(*&^";
//定义接收b；
String b = "";
for (int i = 0; i < a.length(); i++) {
//是否含有数字，有则接收
if ("1234567890".contains(a.charAt(i)+"")) {
b+=a.charAt(i);
}
}
//最后输出
System.out.println(b);