手写代码:给一个字符串找出第一个只出现一次的字符位置
参考回答:
def first_not_repeating_char(string): if not string: return -1 resultDict = {} for k, s in enumerate(string): resultDict [s] = [resultDict [s][0] + 1,k] if resultDict .get(s) else [1,k] pos = len(string) ret = None for x in resultDict : if resultDict [x][0] ==1 and resultDict [x][1] <pos: pos = resultDict [x][1] ret = (x,pos) return ret