正整数A的“DA（为1位整数）部分”定义为由A中所有DA组成的新整数PA。例如：给定A = 3862767，DA = 6，则A的“6部分”PA是66，因为A中有2个6。
现给定A、DA、B、DB，请编写程序计算PA + PB。
[编程题]1016. 部分A+B (15)
import java.util.Scanner;
/**
* @ClassName Main
* @Description TODO
* @Author Wlison
* @Date 2020/3/11 9:38
* @Version 1.0
**/
public class Main {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
while (sc.hasNext()) {
int a = sc.nextInt();
int b = sc.nextInt();
int c = sc.nextInt();
int d = sc.nextInt();
String as = "";
String cs = "";
while(a!=0){
if (a%10==b) as+=b;
a/=10;
}
while(c!=0){
if (c%10==d) cs+=d;
c/=10;
}
a=as.equals("")?0:Integer.parseInt(as);
c=cs.equals("")?0:Integer.parseInt(cs);
System.out.println(a+c);
}
}
}
发表于 2020-03-11 10:32:12
回复(0)
import java.util.Scanner;
public class Test1006 {
public static void main(String[] args) {
Scanner scan = new Scanner(System.in);
int A,DA,B,DB,PA=0,PB=0;
A = scan.nextInt();
DA = scan.nextInt();
B = scan.nextInt();
DB = scan.nextInt();
PA=P(A,DA);
PB=P(B,DB);
System.out.println(PA+PB);
}
public static int P(int A,int DA) {
int PA=0,count=1;
while(A>0) {
if(A%10==DA) {
PA+=count*DA;
count*=10;
}
A/=10;
}
return PA;
}
}
发表于 2020-02-05 15:30:43
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import java.util.Scanner;
public clas***ain {
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
int a = scanner.nextInt(),
da = scanner.nextInt(),
b = scanner.nextInt(),
db = scanner.nextInt(),
pa = 0, pb = 0;
char[] arrayA = String.valueOf(a).toCharArray();
int flag = 0;
for (int i = 0; i < arrayA.length; i++) {
if (arrayA[i] == String.valueOf(da).toCharArray()[0]) {
pa += Math.pow(10, flag) * da;
flag++;
}
}
char[] arrayB = String.valueOf(b).toCharArray();
int flag2 = 0;
for (int i = 0; i < arrayB.length; i++) {
if (arrayB[i] == String.valueOf(db).toCharArray()[0]) {
pb += Math.pow(10, flag2) * db;
flag2++;
}
}
System.out.println(pa + pb);
}
}
发表于 2019-05-16 10:56:43
回复(0)
import java.util.Scanner;
public class Main{
private static int han(String a,int b) {
int p=0;
int o=0;
for(int i=0;i<a.length();i++) {
if(a.charAt(i)-'0'==b) {
p++;
}
}
for(int i=0;i<p;i++) {
o+=b*Math.pow(10, i);
}
return o;
}
public static void main(String[] args) {
Scanner in=new Scanner(System.in);
while(in.hasNext()) {
String a=in.next();
int b=in.nextInt();
String c=in.next();
int d=in.nextInt();
System.out.println(han(a,b)+han(c,d));
}
}
}
发表于 2019-03-08 19:57:18
回复(0)
import java.util.Scanner;
public class Main {
private static Scanner sc;
public static void main(String[] args) {
sc = new Scanner(System.in);
int A = sc.nextInt();
int DA = sc.nextInt();
int PA = 0;
int B = sc.nextInt();
int DB = sc.nextInt();
int PB = 0;
while(A > 0) {
if(A % 10 == DA) {
PA = PA * 10 + DA;
}
A /= 10;
}
while(B > 0) {
if(B % 10 == DB) {
PB = PB * 10 + DB;
}
B /= 10;
}
System.out.println(PA + PB);
}
}
编辑于 2018-09-06 11:14:08
回复(0)
import java.util.Scanner;
/*
输入在一行中依次给出A、DA、B、DB，中间以空格分隔，其中0 < A, B < 1010。
输出描述:
在一行中输出PA + PB的值。
输入例子:
3862767 6 13530293 3
输出例子:
399
*/
/*
author: MR.Yang
date:2018.05.26
*/
/*
思路：用了一个Math.pow(double a,int b)方法（a的b次幂）求P的值
参数a表示底数，b表示指数
传回的数值是double类型
*/
public class Main{
public static void main(String[] args){
Scanner in = new Scanner(System.in);
int A = in.nextInt();
int DA = in.nextInt();
int B = in.nextInt();
int DB = in.nextInt();
Main main = new Main();
int Pa = main.getP(A,DA);
int Pb = main.getP(B,DB);
System.out.println(Pa+Pb);
}
public int getP(int A,int B){
int count = 0;
int P=0;
while(A != 0){
if(A%10 == B){
count++;
}
A = A/10;
}
for(int i=0; i<count; i++){
P = P + ((int)(Math.pow(10,i)))*B;
}
return P;
}
}
发表于 2018-05-26 14:47:57
回复(0)
import java.util.Scanner;public class Main {public static void main(String[] args) {Scanner scanner = newScanner(System.in);int A = scanner.nextInt();int Da = scanner.nextInt();int B = scanner.nextInt();int Db = scanner.nextInt();int pa = calculateP(A, Da);int pb = calculateP(B, Db);System.out.println(pa + pb);scanner.close();}private static int calculateP(int num1, int num2) {int count = 0, newNum = 0;while(num1 != 0) {if(num1 % 10== num2)count++;num1 = num1 / 10;}if(count > 0) {for(inti = 0; i < count; i++) {newNum = newNum * 10+ num2;}}return newNum;}}
发表于 2018-05-21 20:48:03
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//【java】28行若此处写String part ="";case通过率75？因为也可能没匹配到，就是0了import java.util.Scanner;
public class Main {
public static void main(String[] args) {
Scanner scanner = new Scanner(System.in);
String []a = new String[4];
for (int i = 0; i < a.length; i++) {
a[i]=scanner.next();
}
scanner.close();
System.out.println(getPart(a[0],a[1])+getPart(a[2],a[3]));
}
public static int getPart(String str1,String str2) {
char []c = str1.toCharArray();
String part = "0";//若此处写="";case通过率75？？？什么原因
for (int i = 0; i < c.length; i++) {
if (str2.equals(c[i]+"")) {
part=part + str2;
}
}
return Integer.parseInt(part);
}
}
编辑于 2018-04-20 00:11:11
回复(0)
import java.util.Scanner;
public class Main {
public static void main(String[]args)
{
Scanner scan=new Scanner(System.in);
long a,b;
int da,db;
a=scan.nextInt();
da=scan.nextInt();
b=scan.nextInt();
db=scan.nextInt();
System.out.println(getNum(a,da)+getNum(b,db));
}
public static long getNum(long k,int dk)
{
int p=0;
int count=0;
while(k>0)
{
if(k%10==dk)
{
count++;
}
k=k/10;
}
for(int i=0;i<count;i++)
p=p*10+dk;
return p;
}
}
public class Main {
public static void main(String[]args)
{
Scanner scan=new Scanner(System.in);
long a,b;
int da,db;
a=scan.nextInt();
da=scan.nextInt();
b=scan.nextInt();
db=scan.nextInt();
System.out.println(getNum(a,da)+getNum(b,db));
}
public static long getNum(long k,int dk)
{
int p=0;
int count=0;
while(k>0)
{
if(k%10==dk)
{
count++;
}
k=k/10;
}
for(int i=0;i<count;i++)
p=p*10+dk;
return p;
}
}
发表于 2018-04-16 23:18:23
回复(0)
import java.io.BufferedReader;
import java.io.IOException;
import java.io.InputStreamReader;
public class Main {
public static void main(String[] args) throws IOException {
BufferedReader br = new BufferedReader(new InputStreamReader(System.in));
String line = br.readLine();
String[] parameters = line.split(" ");
int PA = 0;
int PB = 0;
int DA = Integer.parseInt(parameters[1]);
int DB = Integer.parseInt(parameters[3]);
for(int i = 0; i < parameters[0].length(); i++) {
if(parameters[0].charAt(i) == parameters[1].charAt(0)) {
PA = PA * 10 + DA;
}
}
for(int i = 0; i < parameters[2].length(); i++) {
if(parameters[2].charAt(i) == parameters[3].charAt(0)) {
PB = PB * 10 + DB;
}
}
System.out.println(PA + PB);
}
}
编辑于 2017-11-15 14:58:57
回复(0)
import java.util.Scanner;
public class Main {
String result;
String A,B,A1,B1;
char DA,DB;
public Main() {
Scanner sc=new Scanner(System.in);
A=sc.next();
A1=sc.next();
B=sc.next();
B1=sc.next();
int a=Integer.parseInt(D(A,A1.charAt(0)));
int b=Integer.parseInt(D(B,B1.charAt(0)));
System.out.println(a+b);
}
public String D(String A,char DA) {
result="";
for(int i=0;i<A.length();i++) {
if(A.charAt(i)==DA)
result+=DA;
}
if(result=="")
result="0";
return result;
}
public static void main(String[] args) {
Main p=new Main();
}
}
发表于 2017-10-21 10:45:18
回复(0)
import java.util.Scanner;
public class Main { public static int method(int A, int Da) { int Pa = 0; int i = 0; while (A > 0) { if (A % 10 == Da) { Pa += Math.pow(10, i) * Da; i++; A /= 10; } else { A /= 10; } } return Pa; } @SuppressWarnings("resource") public static void main(String[] args) { Scanner in = new Scanner(System.in); int A = in.nextInt(); int Da = in.nextInt(); int B = in.nextInt(); int Db = in.nextInt(); System.out.println(method(A, Da) + method(B, Db)); }
}
发表于 2017-09-21 20:02:50
回复(0)
import java.util.Scanner;
public class Main {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
long A = sc.nextLong();
int DA = sc.nextInt();
long B = sc.nextLong();
int DB = sc.nextInt();
System.out.println(transTo(A, DA)+transTo(B, DB));
}
public static int transTo (long a, int b){
char str [] = new String(a+"").toCharArray();
String P ="";
for (char c : str) {
if(Integer.parseInt(c+"")==b){
P = P + b;
}
}
if(P.equals("")){
return 0;
}else{
return Integer.parseInt(P);
}
}
}
发表于 2017-08-14 10:48:00
回复(0)
import java.util.Scanner;
public class Main{
@SuppressWarnings("resource")
public static void main(String[] args) {
int a=0;
int b=0;
int Da = 0;
int Db=0;
Scanner sc = new Scanner(System.in);
a = sc.nextInt();
Da = sc.nextInt();
b = sc.nextInt();
Db = sc.nextInt();
int numa = 0;
String stra = String.valueOf(a);
for(int i =0;i<stra.length();i++){
if(stra.charAt(i)==String.valueOf(Da).charAt(0)){
numa++;
}
}
int numb = 0;
String strb = String.valueOf(b);
for(int i =0;i<strb.length();i++){
if(strb.charAt(i)==String.valueOf(Db).charAt(0)){
numb++;
}
}
System.out.println(getNum(Da,numa)+getNum(Db,numb));
}
public static int getNum(int n,int num){
int a=n;
int b =0;
for(int i=0;i<num;i++){
b+=a;
a=a*10;
}
return b;
}
}
发表于 2017-04-05 14:59:48
回复(0)
import java.util.Scanner;
public class Main {
public static void main(String[] args) {
long A , B;
int D_A ,D_B ;
StringBuffer A_str , B_str;
String P_A = "0" , P_B = "0";
Scanner sc = new Scanner(System.in);
A = sc.nextLong();
D_A = sc.nextInt();
B = sc.nextLong();
D_B = sc.nextInt();
A_str = new StringBuffer(Long.toString(A));
B_str = new StringBuffer(Long.toString(B));
int count_A = 0;
int count_B = 0;
for(int i=0;i<A_str.length();i++){
if(A_str.charAt(i)==(char)(D_A+48)){
count_A ++;
}
}
for(int i=0;i<B_str.length();i++){
if(B_str.charAt(i)==(char)(D_B+48)){
count_B ++;
}
}
for(int i=0;i<count_A;i++){
P_A+=(char)(D_A+48);
}
for(int i=0;i<count_B;i++){
P_B+=(char)(D_B+48);
}
try{
System.out.print(Integer.valueOf(P_A)+Integer.valueOf(P_B));
}
catch (Exception e) {
}
}
}
。。。。写得好乱 好蠢。。不过还是通过了
发表于 2017-01-26 16:59:17
回复(0)
问题信息
通过挑战的用户
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2023-03-13 14:45:49 -
2023-03-13 14:28:57
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