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热度指数:2700
时间限制:C/C++ 1秒,其他语言2秒
空间限制:C/C++ 64M,其他语言128M
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算法知识视频讲解
Suppose a bank has K windows open for service. There is a yellow line
in front of the windows which devides the waiting area into two parts.
All the customers have to wait in line behind the yellow line, until it
is his/her turn to be served and there is a window available. It is
assumed that no window can be occupied by a single customer for more
than 1 hour.
Now given the arriving time T and the processing time P of each
customer, you are supposed to tell the average waiting time of all the customers.
输入描述:
Each input file contains one test case. For each case, the first line contains 2 numbers: N (<=10000) - the total number of customers, and K (<=100) - the number of windows. Then N lines follow, each contains 2 times: HH:MM:SS - the arriving time, and P - the processing time in minutes of a customer. Here HH is in the range [00, 23], MM and SS are both in [00, 59]. It is assumed that no two customers arrives at the same time.
Notice that the bank opens from 08:00 to 17:00. Anyone arrives early will have to wait in line till 08:00, and anyone comes too late (at or after 17:00:01) will not be served nor counted into the average.
输出描述:
For each test case, print in one line the average waiting time of all the customers, in minutes and accurate up to 1 decimal place.
示例1
输入
7 3<br/>07:55:00 16<br/>17:00:01 2<br/>07:59:59 15<br/>08:01:00 60<br/>08:00:00 30<br/>08:00:02 2<br/>08:03:00 10