在python3中,下列程序运行结果为:
strs = ['a', 'ab', 'abc', 'abcd'] dicts ={} for i in range(len(strs)): dicts[i] = strs[i] print(dicts)
strs = ['a', 'ab', 'abc', 'abcd'] dicts ={} for i in range(len(strs)): dicts[i] = strs[i] print(dicts)
[0: 'a', 1: 'ab', 2: 'abc', 3: 'abcd']
{1: 'a', 2: 'ab', 3: 'abc', 4: 'abcd'}
{0: 'a', 1: 'ab', 2: 'abc', 3: 'abcd'}
[1: 'a', 2: 'ab', 3: 'abc', 4: 'abcd']