顺时针打印数字矩阵

旋转矩阵
def traverse(matrix):
    m=len(matrix)
    n=len(matrix[0])
    new_matrix=[]
    for i in range(n):
        new_matrix1=[]
        for j in range(m):
            new_matrix1.append(matrix[j][i])
        new_matrix.append(new_matrix1)
    new_matrix.reverse()
    return new_matrix
返回输出
def printmatrix(matrix):
    array=[]
    while matrix:
        for item in matrix[0]:
            array.append(item)
        del matrix[0]
        if len(matrix)==0:
            break
        matrix=traverse(matrix)
    return array
while True:
    m,n=[int(x) for x in input().split()]
    if m==-1&nbs***bsp;n==-1:
        break
    matrix = [[int(x) for x in input().split()] for j in range(m)]
    result=printmatrix(matrix)
    print(','.join(map(str,result)))

Python Solution

def clock_print(matrix):
    c = []
    while True:
        try:
            c.extend(matrix.pop(0))
            for i in range(len(matrix)-1):
                c.append(matrix[i].pop())
            c.extend(matrix.pop(-1)[::-1])
            for i in range(-len(matrix)+1,0):
                c.append(matrix[-i].pop(0))
        except IndexError:
            break
    return c

while True:
    M,N = [int(i) for i in input().split()]
    if M==-1 and N==-1:
        break
    matrix = [[str(i) for i in input().split()] for m in range(M)]
    result = clock_print(matrix)
    print(','.join(result))