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Dating (20)

[编程题]Dating (20)

热度指数：2464 时间限制：C/C++ 1秒，其他语言2秒空间限制：C/C++ 32M，其他语言64M
算法知识视频讲解

Sherlock Holmes received a note with some strange strings: "Let's date! 3485djDkxh4hhGE 2984akDfkkkkggEdsb
s&hgsfdk d&Hyscvnm". It took him only a minute to figure out that those strange strings are actually referring to the
coded time "Thursday 14:04" -- since the first common capital English letter (case sensitive) shared by the first two
strings is the 4th capital letter 'D', representing the 4th day in a week; the second common character is the 5th capital
letter 'E', representing the 14th hour (hence the hours from 0 to 23 in a day are represented by the numbers from 0 to
9 and the capital letters from A to N, respectively); and the English letter shared by the last two strings is 's' at the 4th
position, representing the 4th minute. Now given two pairs of strings, you are supposed to help Sherlock decode the
dating time.

输入描述:

Each input file contains one test case. Each case gives 4 non-empty strings of no more than 60 characters without white space in 4 lines.

输出描述:

For each test case, print the decoded time in one line, in the format "DAY HH:MM", where "DAY" is a 3-character abbreviation for the days 
in a week -- that is, "MON" for Monday, "TUE" for Tuesday, "WED" for Wednesday, "THU" for Thursday, "FRI" for Friday, "SAT" for 
Saturday, and "SUN" for Sunday. It is guaranteed that the result is unique for each case.

示例1

输入

3485djDkxh4hhGE<br/>2984akDfkkkkggEdsb<br/>s&hgsfdk<br/>d&Hyscvnm

输出

THU 14:04

算法知识视频讲解

Java

yigexiaocainiao


import java.util.*;
public class Main{
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        while (sc.hasNext()) {
            Map<String,String> map = new HashMap<>();
            map.put("A","MON");
            map.put("B","TUE");
            map.put("C","WED");
            map.put("D","THU");
            map.put("E","FRI");
            map.put("F","SAT");
            map.put("G","SUN");
            String s1 = sc.nextLine();
            String s2 = sc.nextLine();
            StringBuilder sb = new StringBuilder();
            int i = 0;
            for (;i<s1.length() && i<s2.length();i++){
                if (s1.charAt(i) == s2.charAt(i) && Character.isUpperCase(s1.charAt(i))){
                    sb.append(map.get(s1.charAt(i)+"") + " ");
                    break;
                }
            }
            for (int j = i+1;j<s1.length() && j<s2.length();j++){
                if (s1.charAt(j) == s2.charAt(j)){
                    if (Character.isDigit(s1.charAt(j))){
                        sb.append("0"+(s1.charAt(j)-48)+":");
                    }else {
                        sb.append(s1.charAt(j)-55 + ":");
                    }
                    break;
                }
            }
            String s3 = sc.nextLine();
            String s4 = sc.nextLine();
            for (int k = 0;k<s3.length() && k<s4.length();k++){
                if (s3.charAt(k) == s4.charAt(k) && Character.isLetterOrDigit(s3.charAt(k))){
                    if (k>9)
                        sb.append(k+"");
                    else
                        sb.append("0"+k);
                    break;
                }
            }
            System.out.println(sb);
        }
    }
}

发表于 2018-11-27 17:00:54 回复(0)