Dating (20)

#include <iostream>
#include <stdio.h>
#include <string.h>

using namespace std;

char day[][4] = {"MON", "TUE", "WED", "THU", "FRI", "SAT", "SUN"};

int main()
{
    char str1[61], str2[61], str3[61], str4[61];
    scanf("%s%s%s%s", str1, str2, str3, str4);
    int len1, len2, len3, len4;
    len1 = strlen(str1); len2 = strlen(str2);
    len3 = strlen(str3); len4 = strlen(str4);
    int idx1=0, d=0, h=0, m=0;
    // 寻找d
    for(; idx1<len1&&idx1<len2; idx1++) {
        if(str1[idx1]>='A' && str1[idx1]<='G') {
            if(str1[idx1] == str2[idx1]) {
                d = (str1[idx1]-'A')+1; break;
            }
        }
    }
    // 寻找h
    for(idx1++; idx1<len1&&idx1<len2; idx1++) {
        if((str1[idx1]>='0'&&str1[idx1]<='9')||(str1[idx1]>='A'&&str1[idx1]<='N')) {
            if(str1[idx1] == str2[idx1]) {
                if(str1[idx1]>='0'&&str1[idx1]<='9') {
                    h = (str1[idx1]-'0');
                } else {
                    h = (str1[idx1]-'A') + 10;
                }
                break;
            }
        }
    }
    // 寻找m
    for(int i=0; i<len3&&i<len4; i++) {
        if((str3[i]>='a'&&str3[i]<='z')||(str3[i]>='A'&&str3[i]<='Z')) {
            if(str3[i] == str4[i]) {
                m = i; break;
            }
        }
    }
    printf("%s %02d:%02d", day[d-1], h, m);
    return 0;
} 

import java.util.*;
public class Main{
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        while (sc.hasNext()) {
            Map<String,String> map = new HashMap<>();
            map.put("A","MON");
            map.put("B","TUE");
            map.put("C","WED");
            map.put("D","THU");
            map.put("E","FRI");
            map.put("F","SAT");
            map.put("G","SUN");
            String s1 = sc.nextLine();
            String s2 = sc.nextLine();
            StringBuilder sb = new StringBuilder();
            int i = 0;
            for (;i<s1.length() && i<s2.length();i++){
                if (s1.charAt(i) == s2.charAt(i) && Character.isUpperCase(s1.charAt(i))){
                    sb.append(map.get(s1.charAt(i)+"") + " ");
                    break;
                }
            }
            for (int j = i+1;j<s1.length() && j<s2.length();j++){
                if (s1.charAt(j) == s2.charAt(j)){
                    if (Character.isDigit(s1.charAt(j))){
                        sb.append("0"+(s1.charAt(j)-48)+":");
                    }else {
                        sb.append(s1.charAt(j)-55 + ":");
                    }
                    break;
                }
            }
            String s3 = sc.nextLine();
            String s4 = sc.nextLine();
            for (int k = 0;k<s3.length() && k<s4.length();k++){
                if (s3.charAt(k) == s4.charAt(k) && Character.isLetterOrDigit(s3.charAt(k))){
                    if (k>9)
                        sb.append(k+"");
                    else
                        sb.append("0"+k);
                    break;
                }
            }
            System.out.println(sb);
        }
    }
}

/首先判断第一个字符串，如果第一个字符串有第一个相同的则进行相应的匹配***作
如果第二个字符相等则输出时刻
然后进行第二个字符串匹配并且在a和z之间
然后输出分钟即可/

import java.io.*;
public class Main {

public static void main(String[] args) throws IOException
{
    BufferedReader reader=new BufferedReader(new InputStreamReader(System.in));
   String first=new String(reader.readLine());
   String secong =new String(reader.readLine());
   String third=new String(reader.readLine());
   String fird=new String(reader.readLine());
   String [] week={"MON","TUE","WED","THU","FRI","SAT","SUN"};
   int flag=0;
   for(int i=0;i<first.length()&&i<secong.length();i++)
   {
       if(first.charAt(i)==secong.charAt(i)&&flag==0&&first.charAt(i)>='A'&&first.charAt(i)<='G')
       {

           System.out.print(week[first.charAt(i)-'A']+' ');
           flag=1;
       }
       else if(first.charAt(i)==secong.charAt(i)&&flag==1)
       {
            if(first.charAt(i)>='0'&&first.charAt(i)<='9')
            {
                System.out.print("0");
                System.out.print(first.charAt(i)+":");
                break;
            }
            else if(first.charAt(i)>='A'&&first.charAt(i)<='N')
            {
                flag=first.charAt(i)-'A'+10;
                System.out.print(flag+":");
                break;
            }
       }
   }

   for(int i=0;i<third.length()&&i<fird.length();i++)
   {
       if(third.charAt(i)==fird.charAt(i)&&fird.charAt(i)>='a'&&fird.charAt(i)<='z')
       {
           if(i<10) {
               System.out.print('0');
               System.out.print(i);
               break;
           }
           else
           {
               System.out.print(i);
               break;
           }
       }
   }


}

}

L=[input() for i in range(4)]
n,m,res=min(len(L[0]),len(L[1])),min(len(L[2]),len(L[3])),[]
week=['MON','TUE','WED','THU','FRI','SAT','SUN']
for i in range(n):
    x,y=L[0][i],L[1][i]
    if not res and x==y and x>='A' and x<='G':
        res.append(week[ord(x)-ord('A')])
    elif len(res)==1 and x==y and ((x>='0' and x<='9') or (x>='A' and x<='Z')):
        t=int(x) if x.isdigit() else ord(x)-ord('A')+10
        res.append(t)
for i in range(m):
    x,y=L[2][i],L[3][i]
    if x==y and x>='A' and x<='z':
        res.append(i)
        break
print('{} {:02d}:{:02d}'.format(res[0],res[1],res[2]))

思路：按部就班。
#include <iostream>
#include <string>

using namespace std;


int main()
{
    string week[] = { "MON","TUE","WED","THU","FRI","SAT","SUN" };
    string n1, n2, n3, n4;
    string rlt;
    int count = 0;
    cin >> n1 >> n2 >> n3 >> n4;
    for (int i = 0; i < n1.size() && i < n2.size(); i++)
    {
        if (n1[i] == n2[i])
        {
            if(!count && (n1[i] >= 'A' && n1[i] <= 'Z'))
                count++;
            else if(count && ((n1[i] >= '0' && n1[i] <= '9') || (n1[i] >='A' && n1[i] <='N')))
            {
                count++;
            }
            if(count == 1)
                rlt += week[n1[i] - 'A'];
            else if(count == 2)
            {
                if (n1[i] >= '0' && n1[i] <= '9')
                {
                    rlt += " 0";
                    rlt += n1[i];
                }
                else
                {
                    rlt += " ";
                    if (n1[i] >= 'A' && n1[i] <= 'J')
                    {
                        rlt += "1";
                        rlt += n1[i] - 'A' + '0';
                    }
                    else
                    {
                        rlt += "2";
                        rlt += n1[i] - 'K' + '0';
                    }
                    
                }
                rlt += ":";
                break;
            }
        }
    }
    for (int i = 0; i < n3.size() && i < n4.size(); i++)
    {
        if (n3[i] == n4[i] && ((n3[i] >= 'a' && n3[i] <= 'z') ||( n3[i] >='A' && n3[i] <= 'Z')))
        {
            rlt += i / 10 + '0';
            rlt += i % 10 + '0';
            break;
        }
    }
    cout << rlt << endl;
    system("pause");
}

s1, s2, s3, s4 = input(), input(), input(), input()
week = ['MON', 'TUE', 'WED', 'THU', 'FRI', 'SAT', 'SUN']
t = [x[0] for x in zip(s1,s2) if x[0]==x[1]]
i = 0
while i<len(t):
    if t[i].isupper():
        break
    i += 1
d, h = t[i], t[i+1]
z = list(zip(s3,s4))
m = [i for i in range(len(z)) if z[i][0]==z[i][1] and z[i][0].isalpha()][0]
day = week[ord(d)-ord('A')]
hh = int(h) if '0'<=h<='9' else ord(h)-ord('A')+10
mm = int(m)
print('{} {:02d}:{:02d}'.format(day,hh,mm))

//没想到这么无脑...
#include <cstdio>
#include <string>
#include <iostream>
using namespace std;
string week[8] = {"00", "MON", "TUE", "WED", "THU",
                  "FRI", "SAT", "SUN"};
int main(){
    string str1, str2, str3, str4;
    cin >> str1 >> str2 >> str3 >> str4;
    int len1 = (str1.length() < str2.length()) ? str1.length() : str2.length();
    int len2 = (str3.length() < str4.length()) ? str3.length() : str4.length();
    int cnt = 1;
    for(int i=0; i<len1; i++){
        if(cnt == 1 && str1[i] == str2[i] && (str1[i] >= 'A' && str1[i] <= 'Z')){
            char c = str1[i];
            int pos = c - 'A' + 1;
            cout << week[pos] << " ";
            cnt ++;
            continue;
        }
        if(cnt == 2 && str1[i] == str2[i] && ((str1[i] >= '0' && str1[i] <= '9')|| (str1[i] >= 'A' && str1[i] <= 'N'))){
            char c = str1[i];
            if(c >= '0' && c <= '9'){
                printf("0%c:", c);
            }
            else if(c >= 'A' && c <= 'N'){
                int min = c - 'A' + 10;
                printf("%d:", min);
            }
            break;
        }
    }
    for(int i=0; i<len2; i++){
        if(str3[i] == str4[i] && ((str4[i] <= 'Z' && str4[i] >= 'A') || (str4[i] >='a' && str4[i] <='z'))){
            printf("%02d\n", i);
            break;
        }
    }
    return 0;
}

#include<iostream>
#include<iomanip>
using namespace std;

int main(){
	string str1,str2,str3,str4;
	int count = 1;
	cin>>str1>>str2>>str3>>str4;
	int n = str1.length() > str2.length() ? str1.length() : str2.length();
	for(int i=0; i<n; i++){
		if(count == 1 && str1[i] == str2[i] && str1[i] >='A' && str1[i] <= 'G'){
			switch(str1[i]){
				case 'A':
					printf("MON ");
					break;
				case 'B':
					printf("TUE ");
					break;
				case 'C':
					printf("WED ");
					break;
				case 'D':
					printf("THU ");
					break;
				case 'E':
					printf("FRI ");
					break;
				case 'F':
					printf("SAT ");
					break; 
				case 'G':
					printf("SUN ");
					break;
			}
			count++;
			continue;
		}
		if(count == 2 && str1[i] == str2[i] && (str1[i] >= '0' && str1[i] <='9' || str1[i] >= 'A' && str1[i] <= 'N')){
			if(str1[i] >= '0' && str1[i] <= '9'){
				printf("%02d:",(int)(str1[i] - '0'));
			}
			else{
				printf("%02d:",(int)(str1[i] - 'A' + 10));
			}
			break;
		}
	}
	n = str3.length() > str4.length() ? str3.length() : str4.length();
	count = 0;
	for(int i=0; i<n; i++){
		if(str3[i] == str4[i] && (str4[i] <= 'Z' && str4[i] >= 'A' || str4[i] >='a' && str4[i] <='z')){
			printf("%02d",i);
			break;
		}
	}
	return 0;
}