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配置文件恢复

[编程题]配置文件恢复

热度指数：114605 时间限制：C/C++ 1秒，其他语言2秒空间限制：C/C++ 32M，其他语言64M
算法知识视频讲解

有6条配置命令，它们执行的结果分别是：

命令	执行
reset	reset what
reset board	board fault
board add	where to add
board delete	no board at all
reboot backplane	impossible
backplane abort	install first
he he	unknown command

注意：he he不是命令。

为了简化输入，方便用户，以“最短唯一匹配原则”匹配（注：需从首字母开始进行匹配）：

1、若只输入一字串，则只匹配一个关键字的命令行。例如输入：r，根据该规则，匹配命令reset，执行结果为：reset what；输入：res，根据该规则，匹配命令reset，执行结果为：reset what；
2、若只输入一字串，但匹配命令有两个关键字，则匹配失败。例如输入：reb，可以找到命令reboot backpalne，但是该命令有两个关键词，所有匹配失败，执行结果为：unknown command

3、若输入两字串，则先匹配第一关键字，如果有匹配，继续匹配第二关键字，如果仍不唯一，匹配失败。

例如输入：r b，找到匹配命令reset board 和 reboot backplane，执行结果为：unknown command。

例如输入：b a，无法确定是命令board add还是backplane abort，匹配失败。

4、若输入两字串，则先匹配第一关键字，如果有匹配，继续匹配第二关键字，如果唯一，匹配成功。例如输入：bo a，确定是命令board add，匹配成功。
5、若输入两字串，第一关键字匹配成功，则匹配第二关键字，若无匹配，失败。例如输入：b addr，无法匹配到相应的命令，所以执行结果为：unknow command。
6、若匹配失败，打印“unknown command”

注意：有多组输入。

数据范围：数据组数： $1\le t\le 800\$ ，字符串长度 $1\le s\le 20\$

进阶：时间复杂度： $O(n)\$ ，空间复杂度： $O(n)\$

输入描述:

多行字符串，每行字符串一条命令

输出描述:

执行结果，每条命令输出一行

示例1

输入

reset
reset board
board add
board delet
reboot backplane
backplane abort

输出

reset what
board fault
where to add
no board at all
impossible
install first

算法知识视频讲解

Python3

Chinry

只需要知道python里面有个神器叫string.startswith()就秒了，而且这个函数还很好记

import sys
while True:
    try:
        command=input()
        if " " not in command and "reset".startswith(command):
            print("reset what")
        elif " " in command and command!="r b" and command!="b a":
            command=command.split(" ")
            #print(command)
            if "reset".startswith(command[0]) and "board".startswith(command[1]):
                print("board fault")
            elif "reboot".startswith(command[0]) and "backplane".startswith(command[1]):
                print("impossible")
            elif "board".startswith(command[0]) and "add".startswith(command[1]):
                print("where to add")
            elif "board".startswith(command[0]) and "delete".startswith(command[1]):
                print("no board at all")
            elif "backplane".startswith(command[0]) and "abort".startswith(command[1]):
                print("install first")
            else:
                print("unknown command")
        else:
            print("unknown command")
    except EOFError:
        sys.exit()

。同理还有个string.endswith()。

发表于 2025-12-13 05:58:34 回复(0)

Python3

大8

import sys

for line in sys.stdin:
    s = line.split()
    if s[0] in "reset" and len(s)==1:
        print("reset what")
    elif len(s)==2:
        if s[0] in 're' and s[1]=='b':
            print("unknown command")
        elif s[0]=='b' and s[1]=='a':
            print("unknown command")
        elif s[0] in "reset" and s[1] in "board":
            print("board fault")
        elif s[0] in "board" and s[1] in "add":
            print("where to add")
        elif s[0] in "board" and s[1] in "delete":
            print("no board at all")
        elif s[0] in "reboot" and s[1] in "backplane":
            print("impossible")
        elif s[0] in "backplane" and s[1] in "abort":
            print("install first")
        else:
            print("unknown command")
    else:
        print("unknown command")

发表于 2025-11-28 14:24:08 回复(0)

Python3

newMar

cmds = {
    "reset": "reset what",
    "reset board": "board fault",
    "board add": "where to add",
    "board delete": "no board at all",
    "reboot backplane": "impossible",
    "backplane abort": "install first"
}

singles = [k for k in cmds if ' ' not in k]
doubles = [k.split() for k in cmds if ' ' in k]

while True:
    try:
        line = input()
        words = line.split()
        
        if len(words) == 1:
            input_word = words[0]
            match = [s for s in singles if s.startswith(input_word)]
            print(cmds[match[0]] if len(match) == 1 else "unknown command")
        elif len(words) == 2:
            input_word1, input_word2 = words
            match =  [cmds[' '.join(d)] for d in doubles if d[0].startswith(input_word1) and d[1].startswith(input_word2)]
            print(match[0] if len(match) == 1 else "unknown command")
        else:
            print("unknown command")
    except:
        break

发表于 2025-11-25 15:13:55 回复(0)

Python3

牛客554682650号

好代码大家看得多了，来看究极屎山代码，虽然屎但不用动脑子

把所有命令可能的缩略词全部找出来。缩略词一样的再注意一下去重就好了

import sys


def find_keys_with_value(dictionary, s):
    matching_keys = []
    for key, value_list in dictionary.items():
        if s in value_list:
            matching_keys.append(key)
    return matching_keys


command = {
    "reset": [],
    "reset board": [],
    "board add": [],
    "board delete": [],
    "reboot backplane": [],
    "backplane abort": [],
}
###reset命令的所有子集
for i in range(1, len("reset") + 1):
    substring = "reset"[:i]
    command["reset"].append(substring)
###reset board命令所有子集
for i in range(1, len("reset") + 1):
    for j in range(1, len("board") + 1):
        substring1 = "reset"[:i]
        substring2 = "board"[:j]
        command["reset board"].append(substring1 + " " + substring2)

###board add命令所有子集
for i in range(1, len("board") + 1):
    for j in range(1, len("add") + 1):
        substring1 = "board"[:i]
        substring2 = "add"[:j]
        command["board add"].append(substring1 + " " + substring2)

###board delete命令所有子集
for i in range(1, len("board") + 1):
    for j in range(1, len("delete") + 1):
        substring1 = "board"[:i]
        substring2 = "delete"[:j]
        command["board delete"].append(substring1 + " " + substring2)

###reboot backplane命令所有子集
for i in range(1, len("reboot") + 1):
    for j in range(1, len("backplane") + 1):
        substring1 = "reboot"[:i]
        substring2 = "backplane"[:j]
        command["reboot backplane"].append(substring1 + " " + substring2)
###backplane abort命令所有子集
for i in range(1, len("backplane") + 1):
    for j in range(1, len("abort") + 1):
        substring1 = "backplane"[:i]
        substring2 = "abort"[:j]
        command["backplane abort"].append(substring1 + " " + substring2)

while True:
    try:
        s = input().strip()
        if not s:  # 如果输入为空，退出循环
            break
        if s in command["reset"]:
            print("reset what")
        elif s in command["reset board"]:
            if s in command["reboot backplane"]:
                print("unknown command")
            else:
                print("board fault")
            
        elif s in command["board add"]:
            if s in command["backplane abort"]:
                print("unknown command")
            else:
                print("where to add") 

        elif s in command["board delete"]:
            print("no board at all")
        elif s in command["reboot backplane"]:
            if s in command["reset board"]:
                print("unknown command")
            else:
                print("impossible")
        elif s in command["backplane abort"]:
            if s in command["board add"]:
                print("unknown command")
            else:
                print("install first")
        else:
            print("unknown command")
    except:
        break

发表于 2025-09-11 23:43:24 回复(0)

Python3

Do_my_best

一心想着把代码写紧凑些

import sys
order_ls = [('reset','reset what'), ('reset board', 'board fault'), ('board add','where to add'), ('board delete', 'no board at all'), ('reboot backplane','impossible'), ('backplane abort', 'install first')]
for line in sys.stdin:
    a = line.strip()
    a = a.split()
    match_keys = list()
    if len(a) == 1:
        match_keys = [y[1] for y in order_ls if len(y[0].split()) == 1 and a[0] == y[0].split()[0][:len(a[0])]]
    elif len(a) == 2:
        match_keys = [y[1] for y in order_ls if len(y[0].split()) == 2 and a[0] == y[0].split()[0][:len(a[0])] and a[1] in y[0].split()[1][:len(a[1])]]
    if len(match_keys) != 1:
        print('unknown command')
    else:
        print(match_keys[0])

发表于 2024-11-27 17:19:46 回复(0)

Python3

Tony_谭

strings = [['reset', 'board'], ['board', 'add'], ['board', 'delete'], ['reboot', 'backplane'], ['backplane', 'abort']]

output = ['board fault', 'where to add', 'no board at all', 'impossible', 'install first']

def match_reset(s, reset='reset'):

i = 0

while i < len(s) and i < len(reset) and s[i] == reset[i]: # 加入边界检查

i += 1

if i == len(s):

return True

return False

def match_mul(s, k):

count = 0

b = []

for idx, x in enumerate(strings): # 使用 enumerate 提前获取索引

i = 0

while i < len(s) and i < len(x[k]) and x[k][i] == s[i]: # 添加索引范围检查

i += 1

if i == len(s):

count += 1

b.append(idx) # 直接存储索引

break

if count == 0:

return [-7, b]

elif count == 1:

return [10, b]

elif count > 1:

return [7, b]

while True:

try:

s = input()

if ' ' in s:

arr = s.split()

X = match_mul(arr[0], 0) # 缓存结果

if X[0] == 7:

j = match_mul(arr[1], 1) # 缓存结果

if j[0] == 10:

print(output[j[1][0]])

elif j[0] == 7:

intersection = set(X[1]) & set(j[1]) # 提前计算交集

if len(intersection) == 0 or len(intersection) > 1:

print('unknown command')

elif len(intersection) == 1:

print(output[intersection.pop()])

elif X[0] == -7:

print('unknown command')

elif X[0] == 10:

print(output[X[1][0]]) # 直接使用缓存结果

else:

if match_reset(s):

print('reset what')

else:

print('unknown command')

except:

break

发表于 2024-11-26 14:42:47 回复(0)

Python3

一个非让他

while True:

try:

comm = ['reset','reset board','board add','board delete','reboot backplane','backplane abort']

com_ex = ['reset what','board fault','where to add','no board at all','impossible','install first']

s = input().strip().split()

if len(s) < 1 or len(s) > 2:

print('unknown command')

else:

if len(s) == 1:

if comm[0].startswith(s[0]):

print(com_ex[0])

else:

print('unknown command')

else:

index = []

for i in range(1,len(comm)):

a = comm[i].split()

if a[0].startswith(s[0]) and a[1].startswith(s[1]):

index.append(i)

if len(index) !=1:

print('unknown command')

else:

print(com_ex[index[0]])

except:

break

发表于 2024-08-23 17:49:07 回复(0)

Python3

XOV_

while True:
    try:
        com_str = input().strip().split()
        key = ["reset", "reset board", "board add", "board delete", "reboot backplane", "backplane abort"]
        value = ["reset what", "board fault", "where to add", "no board at all", "impossible", "install first"]
        if len(com_str) < 1&nbs***bsp;len(com_str) > 2:
            print("unknown command")
        elif len(com_str) == 1:
            if com_str[0] == key[0][0:0 + len(com_str[0])]:
                print(value[0])
            else:
                print("unknown command")
        else:
            num, out = 0, ""
            for index, s in enumerate(key):
                if com_str[0] == s.split()[0][0:0 + len(com_str[0])] and com_str[1] == s.split()[1][0:0 + len(com_str[1])]:
                        num += 1
                        out = value[index]
            if num != 1:
                print("unknown command")
            else:
                print(out)
    except:
        break
为什么我这个预期输出只有一行？  求大佬们指点~

发表于 2024-08-19 18:00:39 回复(0)

Python3

xiaozuo_z

import sys
input = sys.stdin.read
data = input().strip().split('\n')

commands = {
    "reset": "reset what",
    "reset board": "board fault",
    "board add": "where to add",
    "board delete": "no board at all",
    "reboot backplane": "impossible",
    "backplane abort": "install first"
}

def match(c):
    parts = c.split()

    if len(parts) == 1:
        # 只匹配一个关键字的命令
        matched = [cmd for cmd in commands 
        if cmd.startswith(parts[0]) and len(cmd.split()) == 1]
        
        if len(matched) == 1:
            return commands[matched[0]]
        else:
            return "unknown command"  
    
    elif len(parts) == 2:
        matched = [cmd for cmd in commands if cmd.startswith(parts[0])]

        if matched:
            second_matched = [cmd for cmd in matched 
            if len(cmd.split()) > 1 and cmd.split()[1].startswith(parts[1])]

            if len(second_matched) == 1:
                return commands[second_matched[0]]

            else:
                return "unknown command"
        
        else:
            return "unknown command"

    else:
        return "unknown command"

for line in data:
    print(match(line))

发表于 2024-08-14 14:59:52 回复(0)

Python3

迟缓的靓仔在刷题

commands = [

"reset",

"reset board",

"board add",

"board delete",

"reboot backplane",

"backplane abort",

]

results = [

"reset what",

"board fault",

"where to add",

"no board at all",

"impossible",

"install first",

]

def check(line):

s = line.split()

if len(s) < 1 or len(s) > 2:

return "unknown command"

elif len(s) == 1:

if commands[0].startswith(s[0]):

return results[0]

elif len(s) == 2:

res = []

for i in range(1, 6):

item_list = commands[i].split()

if item_list[0].startswith(s[0]) and item_list[1].startswith(s[1]):

res.append(results[i])

if len(res) == 1:

return res[0]

return "unknown command"

while True:

try:

command = input().strip()

print(check(command))

except:

break

发表于 2024-07-13 14:24:40 回复(0)

Python3

immortalcer

import sys
key = [['reset'],['reset','board'],['board','add'],['board','delete'],['reboot','backplane'],['backplane','abort']]
value = ['reset what','board fault','where to add','no board at all','impossible','install first']
def check(line):
    s_input = line.split()
    if len(s_input) == 1:
        if s_input[0] == str(key[0][0][:len(s_input[0])]):
            return value[0]
    elif len(s_input) == 2:
        index = []
        for i in range(1,6):
            if (s_input[0] == str(key[i][0])[:len(s_input[0])]) and (s_input[1] == str(key[i][1])[:len(s_input[1])]):
                index.append(i)
        if len(index) == 1:
            return value[index[0]]
    return 'unknown command'

for line in sys.stdin:
    print(check(line))

发表于 2024-03-30 21:08:52 回复(0)

Python3

牛客1314520

#参考了大佬的代码
import sys
dic = {"reset":"reset what",
    "reset board":"board fault",
    "board add":"where to add",
    "board delete":"no board at all",
    "reboot backplane":"impossible",
    "backplane abort":"install first"}
for a in sys.stdin:
    line = a.split()
    res = []
    for i in dic:
        if len(i.split()) == len(line):
            flag = "True"
            for j in range(len(line)):
                if i.split()[j].startswith(line[j]):
                    pass
                else:
                    flag = "False"
                    break
            if flag == "True":
                res.append(i)
        else:
            flag = "False"
    if len(res) == 1:
        print(dic[res[0]])
    else:
        print("unknown command")

编辑于 2024-02-16 14:02:36 回复(0)

Python3

silence1102

cmd_result = {
    "reset": "reset what",
    "reset board": "board fault",
    "board add": "where to add",
    "board delete": "no board at all",
    "reboot backplane": "impossible",
    "backplane abort": "install first",
    "he he": "unknown command",
}


def execute_cmd(cmd: str):
    cmd_list = cmd.split()
    matched_keys = []
    if len(cmd_list) == 1:
        # 单条命令
        tmp_cmd = cmd_list[0]
        for k in cmd_result:
            if k.startswith("reset") and "reset".startswith(tmp_cmd):
                matched_keys.append(("reset", True))
                break
            if k.startswith(tmp_cmd):
                matched_keys.append((k, k.split() == 1))
    else:
        for k in cmd_result:
            if k != "reset":
                if k.startswith(cmd_list[0]):
                    matched_keys.append((k, False))
        if len(matched_keys) > 0:
            for index, k in enumerate(matched_keys):
                if k[0].split()[-1].startswith(cmd_list[1]):
                    matched_keys[index] = (k[0], True)
    matched_keys = [v for v in matched_keys if v[1]]
    if len(matched_keys) == 1:
        print(cmd_result.get(matched_keys[0][0]))
    else:
        print("unknown command")


while True:
    try:
        cmd_str = input()
        execute_cmd(cmd_str)
    except:
        break

发表于 2023-10-08 22:15:29 回复(0)

Python3

想润的考拉在度假

import sys

d1 = {'reset board':'board fault','board add':'where to add','board delete':'no board at all','reboot backplane':'impossible','backplane abort':'install first'}

def print_command(a:list):

cnt = 0

res = ''

if len(a) == 1:

if ''.join(a) == 'reset'[:len(a[0])]:

print('reset what')

else:

print('unknown command')

elif len(a) == 2:

for x,y in d1.items():

x = x.split()

if a[0] == x[0][:len(a[0])] and a[1] == x[1][:len(a[1])]:

res = y

cnt+=1

if cnt == 1:

print(res)

else:

print('unknown command')

else:

print('unknown command')

for line in sys.stdin:

a = line.split()

print_command(a)

发表于 2023-07-01 23:12:42 回复(0)

Python3

有趣的代码渣渣在吐槽

import re
def func(us=''):
    ml_dict = {
        'reset': 'reset what',
        'reset board': 'board fault',
        'board add': 'where to add',
        'board delete': 'no board at all',
        'reboot backplane': 'impossible',
        'backplane abort': 'install first'
    }
    default_comm = 'unknown command'
    if ' ' in us:
        us_list = us.split()
        ret = [i for i in ml_dict.keys() if ' ' in i
                and re.match(us_list[0], i) and re.search(' ' + us_list[1], i)]
        if len(ret) == 1:
            print(ml_dict.get(ret[0]))
        else:
            print(default_comm)
    else:
        ret = [i for i in ml_dict.keys() if ' ' not in i and re.match(us, i)]
        if len(ret) == 1:
            print(ml_dict.get(ret[0]))
        else:
            print(default_comm)
while True:
    try:
        func(input())
    except:
        break

发表于 2023-04-20 23:49:19 回复(0)

Python3

再多看一眼就会爆炸

最弱智的方法

while True:
    try:
        a=input()
        b=a.split()
        if len(b)==1:
            if a in 'reset':
                print('reset what')
            else:
                print('unknown command')
        elif len(b)==2:
            if not (b[0] in 'reset' and b[1] in 'backplane') and b[0][0]=='r' and b[1][0]=='b':
                if b[0] in 'reset' and b[1] in 'board':
                    print('board fault')
                if b[0] in 'reboot' and b[1] in 'backplane':
                    print('impossible')
            elif not (b[0]=='b' and b[1]=='a') and b[0][0]=='b' and b[1][0]=='a':
                if b[0] in 'board' and b[1] in 'add':
                    print('where to add')
                if b[0] in 'backplane' and b[1] in 'abort':
                    print('install first')
            elif b[0] in 'board' and b[1] in 'delete':
                print('no board at all')
            else:
                print('unknown command')

    except:
        break

发表于 2023-03-12 06:20:43 回复(0)

Python3

clllllllll

我他喵的用了半天树，发现解决不了。。。

发表于 2023-03-04 23:35:31 回复(0)

Python3

在做的机考肯定是必过呀

while True:
    try:
        s = list(input().split())
        d = {'reset':'reset what','reset board':'board fault','board add':'where to add','board delete':'no board at all','reboot backplane':'impossible','backplane abort':'install first','he he':'unknown command'}
        l1 = [['reset','board'],['board','add'],['board','delete'],['reboot','backplane'],['backplane','abort']]
        if len(s) == 1:
            if s[0] == 'reset'[:len(s[0])]:
                print('reset what')
            else:
                print('unknown command')
        elif len(s) == 2:
            chr = ''
            l2 = []
            for i in l1:
                if s[0] == i[0][:len(s[0])] and s[1] == i[1][:len(s[1])]:
                    chr = i[0] + ' ' + i[1]
                    l2.append(chr)
            if len(l2)==1:
                print(d[l2[0]])
            else:
                print('unknown command')
        else:
            print('unknown command')


    except:
        break

发表于 2023-03-01 15:15:58 回复(0)