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Hello World for U

[编程题]Hello World for U

热度指数：14325 时间限制：C/C++ 1秒，其他语言2秒空间限制：C/C++ 64M，其他语言128M
算法知识视频讲解

Given any string of N (>=5) characters, you are asked to form the characters into the shape of U. For example, "helloworld" can be printed as: h d e l l r lowo That is, the characters must be printed in the original order, starting top-down from the left vertical line with n1 characters, then left to right along the bottom line with n2 characters, and finally bottom-up along the vertical line with n3 characters. And more, we would like U to be as squared as possible -- that is, it must be satisfied that n1 = n3 = max { k| k <= n2 for all 3 <= n2 <= N } with n1 + n2 + n3 - 2 = N.

输入描述:

There are multiple test cases.Each case contains one string with no less than 5 and no more than 80 characters in a line. The string contains no white space.

输出描述:

For each test case, print the input string in the shape of U as specified in the description.

示例1

输入

helloworld!
www.nowcoder.com

输出

h   !
e   d
l   l
lowor
w    m
w    o
w    c
.    .
n    r
owcode

算法知识视频讲解

Taitres

发表于 2021-05-11 11:19:51

1.代码实现 #include<iostream> #include<cstdio> using namespace std; int main() { char str[81]; while(scanf("%s",&str)!=EOF){ 展开全文

LoveJK

发表于 2022-01-12 21:49:37

n2随长度增加呈现出一个有规律的数列，从最短长度5开始，n2为：3,4,3,4,5,4,5,6,5,6,7,6,7,8,7,8,9,8,9,10...... #include<iostream> #include<cstring> using namespace std; 展开全文

路人萌Miranda

发表于 2022-03-17 13:42:18

#include <cstdio> #include <string> using namespace std; int main() { string str; while (cin >> str) { int len = str.size(); 展开全文

顶呱呱的火龙果很不想上网课

发表于 2023-02-03 16:46:20

#include <stdio.h> #include <string.h> #include <stdlib.h> int main() { int n, h, w; char s[100]; fgets(s, 100, stdin); 展开全文

牛客861440576号

发表于 2023-02-25 18:16:19

#include "cstdio" #include "string" using namespace std; // 大家用笔和纸画一下就知道了 // 因为 x <= y; 且 2x + y = N - 2 // n1 = n3 = max { k| k <= n2 for al 展开全文

_洋洋_

发表于 2024-03-20 21:53:54

#include<iostream> #include<cstdio> #include<string> using namespace std; int main(){ char arr[100][100]; char buff[100];//暂展开全文

Caiguu

发表于 2021-06-20 16:42:02

知识点绘图，模拟，枚举。可以认为是鸡兔同笼的变式题关键点 And more, we would like U to be as squared as possible -- that is, it must be satisfied that n1 = n3 = max { k| k < 展开全文

DioDid

发表于 2022-01-15 19:56:39

/** * @file StringForU.cpp * @author Shay (837328426@qq.com) * @brief 将字符串变成一个最接近U的形状 * 下面比上面长一个字符 * @date 2022-01-15 */ #include <iostream& 展开全文

Perceive109

发表于 2023-01-10 13:06:25

#include <iostream> #include "string" #include "vector" using namespace std; void getHandW(int size, int &height, int &width) { // 根据初始输入的字符串展开全文

pyp0703

发表于 2024-03-17 14:33:16

#include <stdio.h> int get_length(char s[]) { int i = 0; while (s[i++]); return i - 1; } int main() { char s[80] = {}; while (scanf(" 展开全文

问题信息

字符串

难度：

63条回答 101收藏 6399浏览

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山东大学_杨雪桐

2023-03-06 21:39:58
white3zz1

2023-03-06 15:52:36
牛客91553...

2023-03-03 18:37:48
_cherry

2023-02-28 11:14:32
牛客13702...

2023-02-06 14:50:38

Hello World for U

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