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Magic Coupon (25)

[编程题]Magic Coupon (25)
  • 热度指数:3511 时间限制:C/C++ 1秒,其他语言2秒 空间限制:C/C++ 64M,其他语言128M
  • 算法知识视频讲解
The magic shop in Mars is offering some magic coupons. Each coupon has an integer N printed on it, meaning that when you use this coupon with a product, you may get N times the value of that product back! What is more, the shop also offers some bonus product for free. However, if you apply a coupon with a positive N to this bonus product, you will have to pay the shop N times the value of the bonus product... but hey, magically, they have some coupons with negative N's!
For example, given a set of coupons {1 2 4 -1}, and a set of product values {7 6 -2 -3} (in Mars dollars M$) where a negative value corresponds to a bonus product. You can apply coupon 3 (with N being 4) to product 1 (with value M$7) to get M$28 back; coupon 2 to product 2 to get M$12 back; and coupon 4 to product 4 to get M$3 back. On the other hand, if you apply coupon 3 to product 4, you will have to pay M$12 to the shop.
Each coupon and each product may be selected at most once. Your task is to get as much money back as possible.

输入描述:
Each input file contains one test case.  For each case, the first line contains the number of coupons NC, followed by a line with NC coupon integers.  Then the next line contains the number of products NP, followed by a line with NP product values.  Here 1<= NC, NP <= 105, and it is guaranteed that all the numbers will not exceed 230.


输出描述:
For each test case, simply print in a line the maximum amount of money you can get back.
示例1

输入

4<br/>1 2 4 -1<br/>4<br/>7 6 -2 -3

输出

43

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