对于一个整数X,定义操作rev(X)为将X按数位翻转过来,并且去除掉前导0。例如:
如果 X = 123,则rev(X) = 321;
如果 X = 100,则rev(X) = 1.
现在给出整数x和y,要求rev(rev(x) + rev(y))为多少?
输入为一行,x、y(1 ≤ x、y ≤ 1000),以空格隔开。
输出rev(rev(x) + rev(y))的值
123 100
223
// 很简单 import java.util.Scanner; public class Main { public static void main(String[] args){ Scanner in = new Scanner(System.in); int m = in.nextInt(); int n = in.nextInt(); int out = rev(rev(m)+rev(n)); System.out.println(out); } public static int rev(int num){ int x = 0; while(num!=0){ x = 10*x + num%10; num = num/10; } return x; } }
Integer.parseInt(str)方***自动帮我们去除所有的前导0
import java.util.Scanner;
public class Main {
public static void main(String[] args) {
Scanner sc = new Scanner(System.in);
while (sc.hasNext()) {
String x = sc.next();
String y = sc.next();
int xy = rev(x) + rev(y);
System.out.println(rev(String.valueOf(xy)));
}
sc.close();
}
private static int rev(String s) {
String str = new StringBuilder(s).reverse().toString();
return Integer.parseInt(str);
}
}
#include <stdio.h> #include <sstream> #include <algorithm> using namespace std; int reverseNumber(int x){ string s = to_string(x); reverse(s.begin(),s.end()); return atoi(s.c_str()); } int main(){ int x,y; scanf("%d %d",&x,&y); int temp1 = reverseNumber(x); int temp2 = reverseNumber(y); printf("%d",reverseNumber(temp1+temp2)); return 0; }
import java.util.Scanner;
public class Main{
public static void main(String args[]){
int num1,num2;
Scanner sc = new Scanner(System.in);
num1 = sc.nextInt();
num2 = sc.nextInt();
int result;
result=reverse(reverse(num1)+reverse(num2));
System.out.print(result);
}
public static int reverse(int num) {
StringBuffer sb = new StringBuffer();
//创建空字符串后,append进行追加字符,reverse进行反转,tostring转成string类型
String str = sb.append(num).reverse().toString();
//把String转换成int类型
return Integer.parseInt(str);
}
}
import java.util.Scanner; public class Main { //数字反转 public static void main(String[] args) { Scanner in = new Scanner(System.in); int x = in.nextInt(); int y = in.nextInt(); String xstr = String.valueOf(x); String ystr = String.valueOf(y); x = Integer.valueOf(reverse(xstr)); y = Integer.valueOf(reverse(ystr)); int result = x + y; System.out.println(reverse(String.valueOf(result))); } public static String reverse(String num){ int len = num.length(); int ceil = 1; int rx = 0; for(int i=0; i<len; i++){ rx += Integer.parseInt(num.charAt(i)+"") * ceil; ceil *= 10; } return String.valueOf(rx); } }
#include<stdio.h> #include<math.h> int rev(int x) { int ws=0,x1,x2,i=0,j=0,sum=0,N=0; x1=x; x2=x1; //判断位数 while(x1>=1) { x1/=10; ws++; } //数组对应每个位数 int WS[ws]; while(x2) { WS[i]=x2%10; x2/=10; i++; } while(!WS[j]) { j++; } for(i=j;i<=ws-1;i++) { N=pow(10,ws-i-1); sum+=WS[i]*N; } return sum; } int main() { int x,y,result1,result2,total=0; scanf("%d %d",&x,&y); result1=rev(x); result2=rev(y); total+=result1+result2; printf("%d",rev(total)); return 0; }
import java.util.Scanner;
public class Main {
public static void main(String[] args) {
Scanner s=new Scanner(System.in);
int x=s.nextInt();
int y=s.nextInt();
System.out.print(rev(rev(x)+rev(y)));
}
public static int rev(int i)
{
int a []=new int[20];
int j=0;
int radix=1;
while(i/radix>0)
{
radix=radix*10;
}
radix=radix/10;
int k=0;
while(radix>0)
{
k=i/radix;
a[j++]=k;
i=i-radix*k;
radix=radix/10;
}
String s="";
for(int ii=a.length-1;ii>=0;ii--)
{
s=s+a[ii];
}
int num=Integer.parseInt(s);
return num;
}
}
import java.util.Scanner; public class Main{ public static void main(String []args) { Scanner sc = new Scanner(System.in); //System.out.println("请输入两个整数:"); int x=sc.nextInt(); int y=sc.nextInt(); System.out.println(rever(rever(x)+rever(y))); } public static int rever(int x){ StringBuilder sb=new StringBuilder(String.valueOf(x)); String s=sb.reverse().toString(); while(s.startsWith("0")){ s=s.substring(1); } return Integer.parseInt(s); } }
import java.util.Scanner; public class Main { public static void main(String[] args) { Scanner input = new Scanner(System.in); int x =input.nextInt(); int y =input.nextInt(); System.out.println(Rev(Rev(x)+Rev(y))); } public static int Rev(Integer number) { StringBuilder sb = new StringBuilder(String.valueOf(number)); sb.reverse(); return Integer.valueOf(sb.toString()); } }
Python大法好x,y = input().split(" ") add = int(x[::-1])+int(y[::-1]) add = str(add)[::-1] for i in range(0,len(add)): if(add[i] == '0'): i = i+1 break print(add[i:])
想了想感觉不用判定去首0,那样太束缚Python的灵活了,所以下面有个更简短版的:
x,y = input().split(" ")
add = int(x[::-1])+int(y[::-1])
print(int(str(add)[::-1]))
但是我好奇地对比了一下,第一种方法的运行时间和空间都要优于虽然看上去代码更简短的这种。