使用迭代公式编程求某一正整数a的平方根。

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#include<iostream>
#include<cmath>    
using namespace std;
int main()
{
const double eps = 1e-8;
double a,x0,x;
cout << "please input a:";
cin >> a;
x0 = a / 2;
x = ( x0 + a/x0 )/2;
while( fabs( x-x0 )>eps )
   {
x0 = x;  x =( x0 + a/x0 )/2;
}
cout << x << endl;
}