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Sharing (25)

[编程题]Sharing (25)
  • 热度指数:2309 时间限制:C/C++ 1秒,其他语言2秒 空间限制:C/C++ 64M,其他语言128M
  • 算法知识视频讲解
To store English words, one method is to use linked lists and store a word letter by letter. To save some space, we may let the words share the same sublist if they share the same suffix. For example, "loading" and "being" are stored as showed in Figure 1.
Figure 1 You are supposed to find the starting position of the common suffix (e.g. the position of "i" in Figure 1).

输入描述:
Each input file contains one test case.  For each case, the first line contains two addresses of nodes and a positive N (<= 105), where the two addresses are the addresses of the first nodes of the two words, and N is the total number of nodes.  The address of a node is a 5-digit positive integer, and NULL is represented by -1.
Then N lines follow, each describes a node in the format:
Address Data Next
where Address is the position of the node, Data is the letter contained by this node which is an English letter chosen from {a-z, A-Z}, and Next is the position of the next node.


输出描述:
For each case, simply output the 5-digit starting position of the common suffix.  If the two words have no common suffix, output "-1" instead.
示例1

输入

11111 22222 9<br/>67890 i 00002<br/>00010 a 12345<br/>00003 g -1<br/>12345 D 67890<br/>00002 n 00003<br/>22222 B 23456<br/>11111 L 00001<br/>23456 e 67890<br/>00001 o 00010

输出

67890