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Python3

吐你口水

s = input()

lst = []

flag = 'Good'

for i in s:

if i == 'a':

lst.append(i)

elif i == 'b':

if lst != []:

if lst[-1] == 'a':

lst.pop(-1)

else:

flag = 'Bad'

else:

flag = 'Bad'

if lst != []:

flag = 'Bad'

print(flag)

发表于 2026-01-30 21:24:57 回复(0)

Python3

袁钦照

s = list(input())
list_s = []
dict_s = {
    "b":"a"
}
for i in s:
    if i == "a":
        list_s.append(i)
    elif i in dict_s:
        if not list_s&nbs***bsp;list_s.pop() != dict_s[i]:
            print("Bad")
            break
else:
    if not list_s:
        print("Good")
    else:
        print("Bad")

和括号匹配方法一样

发表于 2025-11-19 15:21:35 回复(0)

Python3

意若久时天然呆

import sys

a, s = "", ""

for line in sys.stdin:

a = line.split()

s = a[0]

while "ab" in s:

s = s.replace("ab", "")

print("Good" if not s else "Bad")

发表于 2025-11-14 09:45:16 回复(0)

Python3

牛客83749222号

s=input().strip()

g=[]

c1,c2=0,0

for i in range(len(s)):

if s[i]=='a':

g.append(s[i])

c1+=1

elif s[i]=='b':

if not g:

print('Bad')

exit()

top = g.pop()

if(top == 'a' and s[i] == 'b'):

c2+=1

if c1==c2:

print('Good')

else:

print('Bad')

发表于 2025-08-18 10:53:36 回复(0)

Python3

牛客116619393号

n = input().strip()

# 核心逻辑：不断删除 "ab" 子串，直到无法删除为止

while "ab" in n:

n = n.replace("ab", "") # 每次删除所有 "ab"（replace 会全局替换）

# 判断最终是否删空

if not n:

print("Good")

else:

print("Bad")

发表于 2025-08-14 13:44:38 回复(0)

Python3

精致的熊熊在努力存钱

class Stock:

def __init__(self) -> None:

self.li = []

def push(self, x):

self.li.append(x)

def pop(self):

return self.li.pop()

def query(self):

return self.li[-1]

def size(self):

return len(self.li)

def empty(self):

return self.li == []

def smatch(s:str):

stock = Stock()

for i in s:

if i == 'a':

stock.push(i)

elif i == 'b':

if stock.empty():

return 'Bad'

stock.pop()

else:

pass

if stock.empty():

return 'Good'

else:

return 'Bad'

if __name__ == '__main__':

s = input()

print(smatch(s))

发表于 2025-07-19 16:36:31 回复(0)

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