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[编程题]Pre-Post
  • 热度指数:2397 时间限制:C/C++ 1秒,其他语言2秒 空间限制:C/C++ 64M,其他语言128M
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We are all familiar with pre-order, in-order and post-order traversals of binary trees. A common problem in data structure classes is to find the pre-order traversal of a binary tree when given the in-order and post-order traversals. Alternatively, you can find the post-order traversal when given the in-order and pre-order. However, in general you cannot determine the in-order traversal of a tree when given its pre-order and post-order traversals. Consider the four binary trees below:
All of these trees have the same pre-order and post-order traversals. This phenomenon is not restricted to binary trees, but holds for general m-ary trees as well.

输入描述:
Input will consist of multiple problem instances. Each instance will consist of a line of the form m s1 s2, indicating that the trees are m-ary trees, s1 is the pre-order traversal and s2 is the post-order traversal.All traversal strings will consist of lowercase alphabetic characters. For all input instances, 1 <= m <= 20 and the length of s1 and s2 will be between 1 and 26 inclusive. If the length of s1 is k (which is the same as the length of s2, of course), the first k letters of the alphabet will be used in the strings. An input line of 0 will terminate the input.


输出描述:
For each problem instance, you should output one line containing the number of possible trees which would result in the pre-order and post-order traversals for the instance. All output values will be within the range of a 32-bit signed integer. For each problem instance, you are guaranteed that there is at least one tree with the given pre-order and post-order traversals.
示例1

输入

2 abc cba
2 abc bca
10 abc bca
13 abejkcfghid jkebfghicda

输出

4
1
45
207352860
头像 csyfZhang
发表于 2020-04-25 16:20:01
是求解给出n叉树的前序和后序遍历,问该n叉树有多少种。 有人已经做过分析了,而且很详细,贴过来过来。如果一遍没看懂,建议多看几遍。https://blog.csdn.net/csyifanZhang/article/details/105751387↑更好的阅读体验(ps:NK的markdown好丑 展开全文
头像 牛客129401600号
发表于 2023-10-26 14:52:13
#include <iostream> const int N = 30; using namespace std; int n; // n叉树 int dp[N][N]; // 组合数 void cal() { dp[0][0] = 1; for 展开全文
头像 Ooops!
发表于 2024-05-22 11:18:17
#include <iostream> #include <cstring> #include<map> #include <algorithm> using namespace std; map<pair<int, int>, lo 展开全文

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