python dict按照value进行排序
f = zip(d.values(),d.keys()) c = sorted(f)
sorted(dict.items(), key = lambda x: x[1])
sorted(dict.items(),key=lambda e:e[1])
from operator import itemgetter list1 = [{"a":9},{"c":1},{"b":2},{"d":10}] dict1 = {k:v for x in list1 for k,v in x.items()} list2 = sorted(dict1.items(),key=itemgetter(1)) print(list2)
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