字符串“a+b=20\n”的长度是()
#include<iostream> #include<string> using namespace std; int main() { char str[] = "a+b=20\n"; int i = sizeof(str); cout << i <<endl; return 0; }
#include <iostream>
#include "string.h"
using namespace std;
int main()
{
char *s = "a+b=20\n";
cout << sizeof(s) << '\n';
cout << strlen(s);
}