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获取有奖金的员工相关信息。

[编程题]获取有奖金的员工相关信息。
  • 热度指数:179597 时间限制:C/C++ 1秒,其他语言2秒 空间限制:C/C++ 32M,其他语言64M
  • 算法知识视频讲解
现有员工表employees如下:
emp_no birth_date first_name last_name gender hire_date
10001 1953-09-02 Georgi
Facello
M
1986-06-26
10002
1964-06-02 Bezalel
Simmel
F
1985-11-21
有员工奖金表emp_bonus:
emp_no recevied btype
10001 2010-01-01 1
10002 2010-10-01 2
有薪水表salaries:
emp_no
salary from_date to_date
10001
60117
1986-06-26
1987-06-26
10001
62102
1987-06-26
1988-06-25
10001
66074
1988-06-25
1989-06-25
10001
66596
1989-06-25
1990-06-25
10001
66961
1990-06-25
1991-06-25
10001
71046
1991-06-25
1992-06-24
10001
74333
1992-06-24
1993-06-24
10001
75286
1993-06-24
1994-06-24
10001
75994
1994-06-24
1995-06-24
10001
76884
1995-06-24
1996-06-23
10001
80013
1996-06-23
1997-06-23
10001
81025
1997-06-23
1998-06-23
10001
81097
1998-06-23
1999-06-23
10001
84917
1999-06-23
2000-06-22
10001
85112
2000-06-22
2001-06-22
10001
85097
2001-06-22
2002-06-22
10001
88958
2002-06-22
9999-01-01
10002
72527
1996-08-03
1997-08-03
10002
72527
1997-08-03
1998-08-03
10002
72527
1998-08-03
1999-08-03
10002
72527
1999-08-03
2000-08-02
10002
72527
2000-08-02
2001-08-02
10002
72527
2001-08-02
9999-01-01
  • 其中bonus类型btype为1其奖金为薪水salary的10%,btype为2其奖金为薪水的20%,其他类型均为薪水的30%。 to_date='9999-01-01'表示当前薪水。
  • 请你给出emp_no、first_name、last_name、奖金类型btype、对应的当前薪水情况salary以及奖金金额bonus,注意只统计有奖金的员工的数据。
  • bonus结果保留一位小数,输出结果按emp_no升序排序。
以上数据集的输出结果如下:
emp_no
first_name
last_name
btype
salary
bonus
10001
Georgi
Facello
1 88958
8895.8000
10002
Bezalel
Simmel
2 72527
14505.4000
示例1

输入

drop table if exists  `employees` ; 
drop table if exists  emp_bonus; 
drop table if exists  `salaries` ; 
CREATE TABLE `employees` (
  `emp_no` int(11) NOT NULL,
  `birth_date` date NOT NULL,
  `first_name` varchar(14) NOT NULL,
  `last_name` varchar(16) NOT NULL,
  `gender` char(1) NOT NULL,
  `hire_date` date NOT NULL,
  PRIMARY KEY (`emp_no`));
 create table emp_bonus(
emp_no int not null,
recevied datetime not null,
btype smallint not null);
CREATE TABLE `salaries` (
`emp_no` int(11) NOT NULL,
`salary` int(11) NOT NULL,
`from_date` date NOT NULL,
`to_date` date NOT NULL,
PRIMARY KEY (`emp_no`,`from_date`));
insert into emp_bonus values
(10001, '2010-01-01',1),
(10002, '2010-10-01',2);
INSERT INTO employees VALUES(10001,'1953-09-02','Georgi','Facello','M','1986-06-26');
INSERT INTO employees VALUES(10002,'1964-06-02','Bezalel','Simmel','F','1985-11-21');

INSERT INTO salaries VALUES(10001,60117,'1986-06-26','1987-06-26');
INSERT INTO salaries VALUES(10001,62102,'1987-06-26','1988-06-25');
INSERT INTO salaries VALUES(10001,66074,'1988-06-25','1989-06-25');
INSERT INTO salaries VALUES(10001,66596,'1989-06-25','1990-06-25');
INSERT INTO salaries VALUES(10001,66961,'1990-06-25','1991-06-25');
INSERT INTO salaries VALUES(10001,71046,'1991-06-25','1992-06-24');
INSERT INTO salaries VALUES(10001,74333,'1992-06-24','1993-06-24');
INSERT INTO salaries VALUES(10001,75286,'1993-06-24','1994-06-24');
INSERT INTO salaries VALUES(10001,75994,'1994-06-24','1995-06-24');
INSERT INTO salaries VALUES(10001,76884,'1995-06-24','1996-06-23');
INSERT INTO salaries VALUES(10001,80013,'1996-06-23','1997-06-23');
INSERT INTO salaries VALUES(10001,81025,'1997-06-23','1998-06-23');
INSERT INTO salaries VALUES(10001,81097,'1998-06-23','1999-06-23');
INSERT INTO salaries VALUES(10001,84917,'1999-06-23','2000-06-22');
INSERT INTO salaries VALUES(10001,85112,'2000-06-22','2001-06-22');
INSERT INTO salaries VALUES(10001,85097,'2001-06-22','2002-06-22');
INSERT INTO salaries VALUES(10001,88958,'2002-06-22','9999-01-01');
INSERT INTO salaries VALUES(10002,72527,'1996-08-03','1997-08-03');
INSERT INTO salaries VALUES(10002,72527,'1997-08-03','1998-08-03');
INSERT INTO salaries VALUES(10002,72527,'1998-08-03','1999-08-03');
INSERT INTO salaries VALUES(10002,72527,'1999-08-03','2000-08-02');
INSERT INTO salaries VALUES(10002,72527,'2000-08-02','2001-08-02');
INSERT INTO salaries VALUES(10002,72527,'2001-08-02','9999-01-01');

输出

10001|Georgi|Facello|1|88958|8895.8
10002|Bezalel|Simmel|2|72527|14505.4

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