/** * * @Title 我是大V * @Description 每个人都想成为大V (VIP:Very Important Person),但要一点一点积累才行,先从小v做起。要求输出由小写字母v组成的大V。 * * @author weijunfu<ijunfu @ qq.com> * @date 2022/03/17 23:48 * @version 1.0.0 * */ public class Main { public static void main(String[] args) { System.out.println("v v\n v v \n v "); } }
public class Main { static char c[][] = new char[3][5]; public static void main(String[] args) { in(c); for (char ch[] : c) { for (char cc : ch) { System.out.print(ch); } System.out.println(); } } public static void in(char c[][]) { for (int i = 0; i < 3; i++) { for (int x = 0; i < 5; i++) { if (x == i || x - 3 == -(i - 3)) c[i][x] = 'v'; else c[i][x] = ' '; } } } }
public class Main{
public static void main(String[] args){
sout(3);
}
public static void sout(int n){ //n为层数 int len = 2*n - 1; //len为层的元素个数 int head = 0; //每层第一个元素的下标 int rear = len-1; //没层最后一个元素的下标 for(int i=n; i>0; i--){ //i为没层层数的下标 for(int j=0; j<len; j++){ //j为没层元素个数的下标 if(j==head || j==rear){ System.out.print("v"); }else{ System.out.print(" "); } } head++; rear--; System.out.println(); } }
}
for (int row = 0;row<3;row++){ for (int i = 0; i < 5 - row; i++) { if (i == row || i == (4 - row)) { System.out.print("v"); } else { System.out.print(" "); } } System.out.print("\n"); }
public class Main { public static void main(String[] args) { //输入层数,打印 Main.Solution(3); } static void Solution(int n) { //每一行v和空格的总数=最高层数+(最高层数-1) int count = n + (n - 1); int head = 1; int end = count; // 控制打印的层数 for (int i = n; i > 0; i--) { // 循环遍历输出当前层的个数和空格 for (int j = 1; j <= count; j++) { if (j == head || j == end) { System.out.print("v"); } else { System.out.print(" "); } } System.out.print("\n"); ++head; --end; } } }
public class Main { public static void main(String[] args) { veryImportantPerson(3); } public static void veryImportantPerson(int n) { int countLeft=0; int countRight=0; for(int i=1;i<=n;i++) { countLeft=i;countRight=2*n-i; for(int j=1;j<=2*n-1;j++) { if(countLeft==j||countRight==j) { System.out.print("v"); }else { System.out.print(" "); } } System.out.print("\n"); } } }