设计函数min(x,y),返回两个double数值中较小的数

[问答题]

设计函数min(x,y),返回两个double数值中较小的数值，同时用一个简单的驱动程序测试该函数。

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蜡蜡

#include<stdio.h>
double min(double ,double );
int main(void)
{
 double x,y;
 printf("input two doubles:");
 scanf("%lf%lf",&x,&y);
 printf("the smaller is:%.2lf\n",min(x,y));
 return(0);
}
double min(double a,double b)
{
 return a<b?a:b;
}

发表于 2018-05-05 21:43:12 回复(0)

骑着小毛驴的W

链接：https://www.nowcoder.com/questionTerminal/2d7793c6367d4be88002320e8f1f474b
来源：牛客网

#include <stdio.h>

doublemin(double,double);

intmain(void)

{

doublex, y;

printf("Input two doubles:");

scanf("%1f%1f", &x, &y);

printf("The smaller is %1.2f", min(x, y));

return0;

}

doublemin(double,double)

{

doublea, b;

returna < b ? a :b;

}

发表于 2019-09-30 14:49:08 回复(0)

扬九

min是C语言里面的math.h的一个函数直接用这个做函数名会报错

发表于 2018-10-17 19:42:53 回复(0)

Icey.Tian

#include <stdio.h>
double min(double, double);
int main(void)
{
    double x, y;
    printf("Input two doubles:");
    scanf("%1f%1f", &x, &y);  
    printf("The smaller is %1.2f", min(x, y));
    return 0;
}
double min(double, double)
{
    double a, b;
    return a < b ? a :b; 
}

编辑于 2018-08-08 13:34:51 回复(0)