const SIZE = 100; var n, i, sum, x : integer; a : array[1..SIZE] of integer; begin readln(n); fillchar(a, sizeof(a), 0); for i := 1 to n do begin read(x); inc(a[x]); end; i := 0; sum := 0; while sum < (n div 2 + 1) do begin inc(i); sum := sum + a[i]; end; writeln(i); end.
输入：
11
4 5 6 6 4 3 3 2 3 2 1
输出：1
