KiKi和BoBo玩 “井”字棋。也就是在九宫格中，只要任意行、列，或者任意对角线上面出现三个连续相同的棋子，就能获胜。请根据棋盘状态，判断当前输赢。
[编程题]井字棋
- 热度指数：22455 时间限制：C/C++ 1秒，其他语言2秒 空间限制：C/C++ 256M，其他语言512M
- 算法知识视频讲解
输入描述:
三行三列的字符元素，代表棋盘状态，字符元素用空格分开，代表当前棋盘，其中元素为K代表KiKi玩家的棋子，为O表示没有棋子，为B代表BoBo玩家的棋子。
输出描述:
如果KiKi获胜，输出“KiKi wins!”；
如果BoBo获胜，输出“BoBo wins!”；
如果没有获胜，输出“No winner!”。
示例1
输入
K O B O K B B O K
输出
KiKi wins!
#include <stdio.h>
int main() {
char c;
int a[3][3], i, j, sum = 0;
int b[8];
for(i = 0; i < 8; i++) //先初始化
{
b[i] = 0;
}
for(i = 0; i < 3; i++)
{
for(j = 0; j < 3; j++)
{
scanf(" %c", &c);
if(c == 'K')
a[i][j] = 1; //本来想试试能不能用矩阵算,发现用C写矩阵乘法函数挺麻烦
else if (c == 'B')
a[i][j] = -1;
else
a[i][j] = 0;
}
}
for(i = 0; i < 3; i++)
{
for(j = 0; j < 3; j++)
{
b[i] += a[i][j];
b[i + 3] += a[j][i];
}
b[6] += a[i][i];
b[7] += a[i][2 - i];
}
for(i = 0; i < 8; i++)
{
b[i] /= 3; //因为b[i]绝对值不超过3,而+-3又是想要的结果,/3就把不想要的去了
sum += b[i]; //题目应该不会出现同时赢的情况吧:)
}
if(!sum)
printf("No winner!\n");
else if(sum > 0)
printf("KiKi wins!\n");
else
printf("BoBo wins!\n");
return 0;
}
发表于 2025-05-07 01:40:27
回复(0)
#include <stdio.h>
int main() {
char arr[3][3] = {0}, a = 'N';
for (int i = 0; i < 3; i++) {
scanf(" %c %c %c", &arr[i][0], &arr[i][1], &arr[i][2]);//录入矩阵
}
for (int i = 0; i < 3; i++) {
if (arr[i][0] == arr[i][1] && arr[i][1] == arr[i][2]) {//行比较
if (arr[i][1] == 'K') {
a = 'K';
} else if (arr[i][1] == 'B') {
a = 'B';
}
}
if (arr[0][i] == arr[1][i] && arr[1][i] == arr[2][i]) {//列比较
if (arr[1][i] == 'K') {
a = 'K';
} else if (arr[1][i] == 'B') {
a = 'B';
}
}
}//X比较
if ((arr[0][0] == arr[1][1] && arr[1][1] == arr[2][2]) ||
(arr[2][0] == arr[1][1] && arr[1][1] == arr[0][2])) {
if (arr[1][1] == 'K') {
a = 'K';
} else if (arr[1][1] == 'B') {
a = 'B';
}
}
if (a == 'B') {//打印
printf("BoBo wins!\n");
} else if (a == 'K') {
printf("KiKi wins!\n");
} else if (a == 'N') {
printf("No winner!\n");
}
return 0;
}
发表于 2025-02-26 21:10:19
回复(0)
#include <stdio.h>
int main() {
char arr[3][3];
for (int i = 0; i < 3; i++) {
for (int j = 0; j < 3; j++) {
scanf(" %c", &arr[i][j]);
}
}
/*
for(int i=0; i<3; i++){
for(int j=0; j<3; j++){
printf("%c ", arr[i][j]);
}
printf("\n");
}*/
int Knum = 0, Bnum = 0;
//行判断
for (int i = 0; i < 3; i++) {
for (int j = 0; j < 3; j++) {
if (arr[i][j] == 'K') {
Knum++;
}
if (arr[i][j] == 'B') {
Bnum++;
}
}
if (Knum == 3 || Bnum == 3) {
if (Knum == 3) {
printf("KiKi wins!");
return 0;
}
if (Bnum == 3) {
printf("BoBo wins!");
return 0;
}
}
Knum = 0;
Bnum = 0;
}
//列判断
for (int i = 0; i < 3; i++) {
for (int j = 0; j < 3; j++) {
if (arr[j][i] == 'K') {
Knum++;
//printf("%d ", Knum);
}
if (arr[j][i] == 'B') {
Bnum++;
}
}
if (Knum == 3 || Bnum == 3) {
if (Knum == 3) {
printf("KiKi wins!");
return 0;
}
if (Bnum == 3) {
printf("BoBo wins!");
return 0;
}
}
Knum = 0;
Bnum = 0;
}
//左斜判断
for (int i = 0; i < 3; i++) {
if (arr[i][i] == 'K') {
Knum++;
//printf("%d ", Knum);
}
if (arr[i][i] == 'B') {
Bnum++;
}
if (Knum == 3 || Bnum == 3) {
if (Knum == 3) {
printf("KiKi wins!");
return 0;
}
if (Bnum == 3) {
printf("BoBo wins!");
return 0;
}
}
}
Knum = 0;
Bnum = 0;
//右斜判断
for (int i = 0; i < 3; i++) {
if (arr[i][2 - i] == 'K') {
Knum++;
}
if (arr[i][2 - i] == 'B') {
Bnum++;
}
if (Knum == 3 || Bnum == 3) {
if (Knum == 3) {
printf("KiKi wins!");
return 0;
}
if (Bnum == 3) {
printf("BoBo wins!");
return 0;
}
}
}
Knum = 0;
Bnum = 0;
//无人获胜
printf("No winner!");
return 0;
}
编辑于 2024-02-10 18:26:45
回复(0)
#include <stdio.h>
int main() {
char arr[3][3] = {0};
int i = 0;
int j = 0;
char flag = 'c';
for (i = 0; i < 3; i++) {
for (j = 0; j < 3; j++) {
scanf("%c", &arr[i][j]);
getchar();
}
}
for (i = 0; i < 3; i++) {
if (arr[i][0] == arr[i][1] && arr[i][1] == arr[i][2]) {
flag = arr[i][1];
break;
}
if (arr[0][i] == arr[1][i] && arr[1][i] == arr[2][i]) {
flag = arr[1][i];
break;
}
}
if (arr[0][0] == arr[1][1] && arr[1][1] == arr[2][2]) {
flag = arr[1][1];
}
if (arr[0][2] == arr[1][1] && arr[1][1] == arr[2][0]) {
flag = arr[1][1];
}
if (flag == 'K')
printf("KiKi wins!");
else if (flag == 'B')
printf("BoBo wins!");
else
printf("No winner!");
return 0;
}
发表于 2024-01-24 23:33:31
回复(0)
#define _CRT_SECURE_NO_WARNINGS 1
#include<stdio.h>
int main()
{
int a = 0;
int b = 0;
int flage = 0;
char arr[10] = { 0 };
for (int i = 1; i < 10; i++)
{
scanf("%c", &arr[i]);
if (arr[i] == ' '||arr[i]=='\n')
{
i--;
}
}
for (int i = 1; i < 10; i++)
{
if (arr[i] == 'K')
{
a = i;
break;
}
}
switch (a)
{
case 1:
if (arr[2] == 'K' && arr[3] == 'K')
{
flage = 1;
}
if (arr[4] == 'K' && arr[7] == 'K')
{
flage = 1;
}
if (arr[5] == 'K' && arr[9] == 'K')
{
flage = 1;
}
break;
case 2:
if (arr[5] == 'K' && arr[8] == 'K')
{
flage = 1;
}
break;
case 3:
if (arr[6] == 'K' && arr[9] == 'K')
{
flage = 1;
}
if (arr[5] == 'K' && arr[7] == 'K')
{
flage = 1;
}
break;
case 4:
if (arr[5] == 'K' && arr[6] == 'K')
{
flage = 1;
}
break;
case 7:
if (arr[8] == 'K' && arr[9] == 'K')
{
flage = 1;
}
break;
}
if (flage == 1)
{
printf("KiKi wins!");
}
else
{
for (int i = 1; i < 10; i++)
{
if (arr[i] == 'B')
{
b = i;
break;
}
}
switch (b)
{
case 1:
if (arr[2] == 'B' && arr[3] == 'B')
{
flage = 1;
}
if (arr[4] == 'B' && arr[7] == 'B')
{
flage = 1;
}
if (arr[5] == 'B' && arr[9] == 'B')
{
flage = 1;
}
break;
case 2:
if (arr[5] == 'B' && arr[8] == 'B')
{
flage = 1;
}
break;
case 3:
if (arr[6] == 'B' && arr[9] == 'B')
{
flage = 1;
}
if (arr[5] == 'B' && arr[7] == 'B')
{
flage = 1;
}
break;
case 4:
if (arr[5] == 'B' && arr[6] == 'B')
{
flage = 1;
}
break;
case 7:
if (arr[8] == 'B' && arr[9] == 'B')
{
flage = 1;
}
break;
}
if (flage == 1)
{
printf("BoBo wins!");
}
else
{
printf("No winner!");
}
}
return 0;
}
#include<stdio.h>
int main()
{
int a = 0;
int b = 0;
int flage = 0;
char arr[10] = { 0 };
for (int i = 1; i < 10; i++)
{
scanf("%c", &arr[i]);
if (arr[i] == ' '||arr[i]=='\n')
{
i--;
}
}
for (int i = 1; i < 10; i++)
{
if (arr[i] == 'K')
{
a = i;
break;
}
}
switch (a)
{
case 1:
if (arr[2] == 'K' && arr[3] == 'K')
{
flage = 1;
}
if (arr[4] == 'K' && arr[7] == 'K')
{
flage = 1;
}
if (arr[5] == 'K' && arr[9] == 'K')
{
flage = 1;
}
break;
case 2:
if (arr[5] == 'K' && arr[8] == 'K')
{
flage = 1;
}
break;
case 3:
if (arr[6] == 'K' && arr[9] == 'K')
{
flage = 1;
}
if (arr[5] == 'K' && arr[7] == 'K')
{
flage = 1;
}
break;
case 4:
if (arr[5] == 'K' && arr[6] == 'K')
{
flage = 1;
}
break;
case 7:
if (arr[8] == 'K' && arr[9] == 'K')
{
flage = 1;
}
break;
}
if (flage == 1)
{
printf("KiKi wins!");
}
else
{
for (int i = 1; i < 10; i++)
{
if (arr[i] == 'B')
{
b = i;
break;
}
}
switch (b)
{
case 1:
if (arr[2] == 'B' && arr[3] == 'B')
{
flage = 1;
}
if (arr[4] == 'B' && arr[7] == 'B')
{
flage = 1;
}
if (arr[5] == 'B' && arr[9] == 'B')
{
flage = 1;
}
break;
case 2:
if (arr[5] == 'B' && arr[8] == 'B')
{
flage = 1;
}
break;
case 3:
if (arr[6] == 'B' && arr[9] == 'B')
{
flage = 1;
}
if (arr[5] == 'B' && arr[7] == 'B')
{
flage = 1;
}
break;
case 4:
if (arr[5] == 'B' && arr[6] == 'B')
{
flage = 1;
}
break;
case 7:
if (arr[8] == 'B' && arr[9] == 'B')
{
flage = 1;
}
break;
}
if (flage == 1)
{
printf("BoBo wins!");
}
else
{
printf("No winner!");
}
}
return 0;
}
编辑于 2024-01-04 15:46:45
回复(2)
#include <stdio.h>
//应该还能简化，先写成这样吧
char tic_alg(char tic[3][3])
{
char flag = 'O';
for (int i = 0; i < 3; i++)
{
//判断横排
if (tic[i][0] == tic[i][1] && tic[i][1] == tic[i][2])
{
if (tic[i][1] != 'O')
{
flag = tic[i][1];
break;
}
}
//判断竖排
if (tic[0][i] == tic[1][i] && tic[1][i] == tic[2][i])
{
if (tic[i][1] != 'O')
{
flag = tic[1][i];
break;
}
}
}
//判断对角线
if ((tic[0][0] == tic[1][1] && tic[1][1] == tic[2][2]) || (tic[2][0] == tic[1][1] && tic[1][1] == tic[0][2]))
{
if (tic[1][1] != 'O')
{
flag = tic[1][1];
}
}
return flag;
}
int main()
{
char tic[3][3] = {0};
for (int i = 0; i < 3; i++)
{
for (int j = 0; j < 3; j++)
{
scanf(" %c", &tic[i][j]);
}
}
char ret = tic_alg(tic);
if ('K' == ret)
{
printf("KiKi wins!\n");
}
else if ('B' == ret)
{
printf("BoBo wins!\n");
}
else
{
printf("No winner!\n");
}
return 0;
}
发表于 2023-11-30 00:23:41
回复(0)
#include <stdio.h>
int main()
{
char arr[3][3];
int i;
int count = 0;
for(i=0;i<3;i++)
{
int j;
for(j=0;j<3;j++)
{
scanf("%c ",arr[i]+j);
}
}
//每一行
int flag = 0;
for(i=0;i<3;i++)
{
int j;
for(j=0;j<2;j++)
{
if(arr[i][j] == arr[i][j+1])
{
flag++;
}
}
if(flag == 2)
{
if(arr[i][j]=='K')
{
printf("KiKi wins!");
count = 1;
}
if(arr[i][j]=='B')
{
printf("BoBo wins!");
count = 1;
}
}
flag = 0;
}
//每一列
flag = 0;
for(i=0;i<3;i++)
{
int j;
for(j=0;j<2;j++)
{
if(arr[j][i] == arr[j+1][i])
{
flag++;
}
}
if(flag == 2)
{
if(arr[j][i]=='K')
{
printf("KiKi wins!");
count = 1;
}
if(arr[j][i]=='B')
{
printf("BoBo wins!");
count = 1;
}
}
flag = 0;
}
//对角线
if(arr[0][0]==arr[1][1]&&arr[1][1]==arr[2][2])
{
if(arr[1][1] == 'K')
{
printf("KiKi wins!");
count = 1;
}
if(arr[1][1] == 'B')
{
printf("BoBo wins!");
count = 1;
}
}
if(arr[0][2]==arr[1][1]&&arr[1][1]==arr[2][0])
{
if(arr[1][1] == 'K')
{
printf("KiKi wins!");
count = 1;
}
if(arr[1][1] == 'B')
{
printf("BoBo wins!");
count = 1;
}
}
//都没赢
if(count == 0)
{
printf("No winner!");
}
return 0;
}
发表于 2023-11-13 11:04:35
回复(0)
#include <stdio.h>
int main()
{
int i,j,bi=0,bj=0,ki=0,kj=0;
char a[3][3]={0};
for(i=1;i<=3;i++)
{
for(j=1;j<=3;j++)
scanf("%c ",&a[i][j]);//输入
}
for(i=1;i<=3;i++)
{
for(j=1;j<=3;j++)
{
if(a[i][j]=='B')
{
bi+=i;//坐标相加
bj+=j;
}
if(a[i][j]=='K')
{
ki+=i;
kj+=j;
}
}
}
if(bi%3==0&&bj%3==0)//一行、一列、对角线的坐标加起来均是3的倍数
printf("BoBo wins!");
else if(ki%3==0&&kj%3==0)
printf("KiKi wins!");
else
printf("No winner!");
return 0;
}
发表于 2023-08-22 21:52:29
回复(0)
#include <stdio.h>
int main(){
int count_B = 0, count_K = 0, isKiki = 1, isBobo = 1;
char arr[3][3];
int row[3] = {0};
int column[3] = {0};
for(int i = 0; i < 3; i++){
for(int j = 0; j < 3; j++){
scanf("%c",&arr[i][j]);
if(arr[i][j] == 'O'){
row[i] = 1;
column[j] = 1;
}
getchar();
}
}
for(int i = 0; i < 3; i++){
if(row[i] == 0){
for(int j = 0; j < 2; j++){
if(arr[i][j] != arr[i][j+1]){
isKiki = 0;
isBobo = 0;
break;
}
}
if(isBobo == 0){
isBobo = 1;
isKiki = 1;
break;
} else if(arr[i][0] == 'K'){
printf("KiKi wins!");
return 0;
} else {
printf("BoBo wins!");
return 0;
}
}
}
for(int j = 0; j < 3; j++){
if(column[j] == 0){
for(int i = 0; i < 2; i++){
if(arr[i][j] != arr[i+1][j]){
isKiki = 0;
isBobo = 0;
break;
}
}
if(isBobo == 0){
isBobo = 1;
isKiki = 1;
break;
} else if(arr[0][j] == 'K'){
printf("KiKi wins!");
return 0;
} else {
printf("BoBo wins!");
return 0;
}
}
}
for(int i = 0; i < 3; i++){
if(arr[i][i] == 'K'){
count_K++;
} else if(arr[i][i] == 'B'){
count_B++;
}
}
if(count_K == 3){
printf("KiKi wins!");
return 0;
} else if(count_B == 3) {
printf("BoBo wins!");
return 0;
} else {
count_B = 0;
count_K = 0;
}
for(int i = 0; i < 3; i++){
if(arr[i][2-i] == 'K'){
count_K++;
} else if(arr[i][2-i] == 'B'){
count_B++;
}
}
if(count_K == 3){
printf("KiKi wins!");
return 0;
} else if(count_B == 3){
printf("BoBo wins!");
return 0;
} else {
printf("No winner!");
}
return 0;
}
这就是所谓的shit mountain吧！
发表于 2022-08-23 12:16:06
回复(0)
#include<stdio.h>
int main() {
char arr[3][3] = {0};
for (int i = 0; i < 3; i++) {
for (int j = 0; j < 3; j++) {
arr[i][j] = getchar();
getchar();
}
}
char ret = 0;//接收游戏情况，'K'KiK赢，'B'BoBo赢，0平局
for (int i = 0; i < 3; i++) {
//横向
if (arr[i][0] != 'O' && arr[i][0] == arr[i][1] && arr[i][0] == arr[i][2]) {
ret = arr[i][0];
break;
}
//纵向
else if (arr[0][i] != 'O' && arr[0][i] == arr[1][i] && arr[0][i] == arr[2][i]) {
ret = arr[0][i];
break;
}
}
//主对角
if (arr[0][0] != 'O' && arr[0][0] == arr[1][1] && arr[0][0] == arr[2][2])
ret = arr[0][0];
else if (arr[0][2] != 'O' && arr[0][2] == arr[1][1] && arr[0][2] == arr[2][0])
ret = arr[0][2];
if (ret == 'K')
printf("KiKi wins!\n");
else if (ret == 'B')
printf("BoBo wins!\n");
else
printf("No winner!\n");
return 0;
}
发表于 2022-08-06 17:06:31
回复(0)
#include <stdio.h>
int main()
{
char a[3][3];
char f = 'O';
for(int i = 0; i < 3; i++)
{
for(int j = 0; j < 3; j++)
scanf("%c ", &a[i][j]);
}
for(int i = 0; i < 3; i++)
{
if(a[i][0]==a[i][1] && a[i][1]==a[i][2])
{
if(a[i][0]=='K')
f = 'K';
else if(a[i][0]=='B')
f = 'B';
}
}
for(int j = 0; j < 3; j++)
{
if(a[0][j]==a[1][j] && a[1][j]==a[2][j])
{
if(a[0][j]=='K')
f = 'K';
else if(a[0][j]=='B')
f = 'B';
}
}
if(a[0][0]==a[1][1] && a[1][1]==a[2][2])
{
if(a[1][1]=='K')
{
f = 'K';
//printf("K\n");
}
else if(a[1][1]=='B')
f = 'B';
}
if(a[0][2]==a[1][1] && a[1][1]==a[2][0])
{
if(a[1][1]=='K')
f = 'K';
else if(a[1][1]=='B')
f = 'B';
}
if(f != 'O')
{
if(f == 'K')
printf("KiKi wins!");
if(f == 'B')
printf("BoBo wins!");
}
else
printf("No winner!");
return 0;
}
发表于 2022-07-05 11:41:45
回复(0)
#include <stdio.h>
#define ROW 3
#define COL 3
char judge(char board[ROW][COL], int row, int col){
for(int i = 0; i < row; i++){
if(board[i][0] == board[i][1] && board[i][1] == board[i][2] && board[i][0] != ' ') //行判断
return board[i][0];
if(board[0][i] == board[1][i] && board[1][i] == board[2][i] && board[0][i] != ' ') //列判断
return board[0][i];
}
if(board[0][0] == board[1][1] && board[1][1] == board[2][2] && board[1][1] != ' ') //对角线
return board[1][1];
if(board[0][2] == board[1][1] && board[1][1] == board[2][0] && board[1][1] != ' ') //斜对角线
return board[1][1];
return ' ';
}
int main(){
char board[ROW][COL];
for(int i = 0; i < ROW; i++){
for(int j = 0; j < COL; j++)
scanf("%c ", &board[i][j]);
}
char status = judge(board, ROW, COL);
if(status == 'K')
printf("KiKi wins!");
else if (status == 'B')
printf("BoBo wins!");
else
printf("No winner!");
return 0;
}
发表于 2022-06-13 15:43:19
回复(2)
#include<stdio.h>
int main()
{
char arr[3][3] = {0};
char result = 0; //用来判断游戏最终结果
int i = 0;
for(i = 0;i<3;i++)
{
int j = 0;
for(j = 0;j<3;j++)
scanf("%c ",&arr[i][j]);
}
for(i = 0;i<3;i++) //判断行or列有没有三个连着的元素相等
{
if(arr[i][0] == arr[i][1] && arr[i][1] == arr[i][2])
{
result = arr[i][0];
break;
}
if(arr[0][i] == arr[1][i] && arr[1][i] == arr[2][i])
{
result = arr[0][i];
break;
}
}
if(arr[0][0] == arr[1][1] && arr[1][1] == arr[2][2]) //判断主对角线
result = arr[0][0];
if(arr[0][2] == arr[1][1] && arr[1][1] == arr[2][0]) //判断副对角线
result = arr[0][2];
if(result == 'K')
printf("KiKi wins!\n");
else if(result == 'B')
printf("BoBo wins!\n");
else
printf("No winner!\n");
return 0;
}
发表于 2022-05-11 00:30:08
回复(0)
#include<stdio.h>
char is_win(char arr[3][3])
{
int i,j;
for(i=0;i<3;i++)
{
if(arr[i][0]==arr[i][1]&&arr[i][1]==arr[i][2]&&arr[i][1]!='O')
return arr[i][1];
}
for(j=0;j<3;j++)
{
if(arr[0][j]==arr[1][j]&&arr[1][j]==arr[2][j]&&arr[1][j]!='O')
return arr[1][j];
}
if((arr[0][0]==arr[1][1]&&arr[1][1]==arr[2][2]&&arr[1][1]!='O')||(arr[0][2]==arr[1][1]&&arr[1][1]==arr[2][0]&&arr[1][1]!='O'))
return arr[1][1];
return 0;
}
int main()
{
char Ki;
int i,j;
char arr[3][3]={0};
for(i=0;i<3;i++)
{
for(j=0;j<3;j++)
{
scanf("%c",&Ki);
getchar();
arr[i][j]=Ki;
}
}
char ret=is_win(arr);
if(ret=='K')
{
printf("KiKi wins!\n");
}
else if(ret=='B')
{
printf("BoBo wins!\n");
}
else
printf("No winner!\n");
return 0;
}
发表于 2022-05-01 11:47:50
回复(0)
#include <stdio.h>
int main()
{
char arr[3][3]={ 0 };
int i = 0;
int j = 0;
for(i=0;i<3;i++)
{
for(j=0;j<3;j++)
{
if(j<2)
scanf("%c ",&arr[i][j]);
else
scanf("%c\n",&arr[i][j]);
}
}
//判断横向
for(i=0;i<3;i++)
{
for(j=0;j<3;j++)
{
if(arr[i][j]!=arr[i][j+1])
{
break;
}
if(1==j)
{
if(arr[i][j]=='K')
printf("KiKi wins!");
else
printf("BoBo wins!");
return 0;
}
}
}
//判断纵向
for(j=0;j<3;j++)
{
for(i=0;i<3;i++)
{
if(arr[i][j]!=arr[i+1][j])
{
break;
}
if(1==i)
{
if(arr[i][j]=='K')
printf("KiKi wins!");
else if(arr[i][j]=='B')
printf("BoBo wins!");
else
continue;
return 0;
}
}
}
//判断对角
for(i=0,j=0;i<3||j<3;i++,j++)
{
if(arr[i][j]!=arr[i+1][j+1])
{
break;
}
if(i==1&&j==1)
{
if(arr[i][j]=='K')
printf("KiKi wins!");
else if(arr[i][j]=='B')
printf("BoBo wins!");
else
continue;
return 0;
}
}
for(i=0,j=2;i<3||j>=0;i++,j--)
{
if(arr[i][j]!=arr[i+1][j-1])
{
break;
}
if(i==1&&j==1)
{
if(arr[i][j]=='K')
printf("KiKi wins!");
else if(arr[i][j]=='B')
printf("BoBo wins!");
else
continue;
return 0;
}
}
printf("No winner!");
}
发表于 2022-03-29 11:03:49
回复(0)
#include<stdio.h>
#include<math.h>
int main(void)
{
char str[3][3];
int i,j,flag1,flag2[3]={0};
for(i=0;i<3;i++){
flag1=0;
for(j=0;j<3;j++){
scanf("%c",&str[i][j]);
getchar();
if (str[i][j]=='K'){flag1++;flag2[j]+=1*pow(3,i);}
else if(str[i][j]=='B'){flag1--;flag2[j]+=2*pow(3,i);}
}
if(flag1==3){printf("KiKi wins!");return 0;}
if(flag1==-3){printf("BoBo wins!");return 0;}//横向三连
}
if(flag2[0]==13||flag2[1]==13||flag2[2]==13){printf("KiKi wins!");return 0;}
if(flag2[0]==26||flag2[1]==26||flag2[2]==26){printf("BoBo wins!");return 0;}//竖向三连(三进制)
if(str[1][1]=='O'){printf("No winner!");return 0;}
else if(str[1][1]=='K')
{
if((str[0][0]=='K'&&str[2][2]=='K') || (str[0][2]=='K'&&str[2][0]=='K')){printf("KiKi wins!");return 0;}
}
else if(str[1][1]=='B')
{
if((str[0][0]=='B'&&str[2][2]=='B') || (str[0][2]=='B'&&str[2][0]=='B')){printf("BoBo wins!");return 0;}
}//斜向三连
}
#include<math.h>
int main(void)
{
char str[3][3];
int i,j,flag1,flag2[3]={0};
for(i=0;i<3;i++){
flag1=0;
for(j=0;j<3;j++){
scanf("%c",&str[i][j]);
getchar();
if (str[i][j]=='K'){flag1++;flag2[j]+=1*pow(3,i);}
else if(str[i][j]=='B'){flag1--;flag2[j]+=2*pow(3,i);}
}
if(flag1==3){printf("KiKi wins!");return 0;}
if(flag1==-3){printf("BoBo wins!");return 0;}//横向三连
}
if(flag2[0]==13||flag2[1]==13||flag2[2]==13){printf("KiKi wins!");return 0;}
if(flag2[0]==26||flag2[1]==26||flag2[2]==26){printf("BoBo wins!");return 0;}//竖向三连(三进制)
if(str[1][1]=='O'){printf("No winner!");return 0;}
else if(str[1][1]=='K')
{
if((str[0][0]=='K'&&str[2][2]=='K') || (str[0][2]=='K'&&str[2][0]=='K')){printf("KiKi wins!");return 0;}
}
else if(str[1][1]=='B')
{
if((str[0][0]=='B'&&str[2][2]=='B') || (str[0][2]=='B'&&str[2][0]=='B')){printf("BoBo wins!");return 0;}
}//斜向三连
}
发表于 2022-03-07 22:27:21
回复(0)
因为固定了三行三列，所以穷举了赢的几种可能
#include<stdio.h>
int main(){
int i,j,k,flag=0;
char a[3][3];
for(i=0;i<3;i++){
for(j=0;j<3;j++){
scanf(" %c",&a[i][j]);//%c前加空格吸收回车
}
}
for(j=0;j<3;j++){
if(a[j][0]=='K'&&a[j][1]=='K'&&a[j][2]=='K'){
printf("KiKi wins!");
flag=1;
break;
}
if(a[0][j]=='K'&&a[1][j]=='K'&&a[2][j]=='K'){
printf("KiKi wins!");
flag=1;
break;
}
if(a[0][0]=='K'&&a[1][1]=='K'&&a[2][2]=='K'){
printf("KiKi wins!");
flag=1;
break;
}
if(a[0][2]=='K'&&a[1][1]=='K'&&a[2][0]=='K'){
printf("KiKi wins!");
flag=1;
break;
}
if(a[j][0]=='B'&&a[j][1]=='B'&&a[j][2]=='B'){
printf("BoBo wins!");
flag=1;
break;
}
if(a[0][j]=='B'&&a[1][j]=='B'&&a[2][j]=='B'){
printf("BoBo wins!");
flag=1;
break;
}
if(a[0][0]=='B'&&a[1][1]=='B'&&a[2][2]=='B'){
printf("BoBo wins!");
flag=1;
break;
}
if(a[0][2]=='B'&&a[1][1]=='B'&&a[2][0]=='B'){
printf("BoBo wins!");
flag=1;
break;
}
}
if(flag==0){
printf("No winner!");
}
return 0;
}
发表于 2022-02-27 12:15:28
回复(0)
#include<stdio.h>//用一个最笨的思路555
int main()
{
int i,j,k,b,z[9]={0},h1=0,h2=0,h3=0,s1=0,s2=0,s3=0,xz=0,xy=0;
char a[9];
for(i=0;i<9;i++)
{
scanf(" %c",&a[i]);
if(a[i]=='K')
z[i]=1;
else if(a[i]=='B')
z[i]=-1;
else if(a[i]=='O')
z[i]=0;
}
h1=z[0]+z[1]+z[2];
h2=z[3]+z[4]+z[5];
h3=z[6]+z[7]+z[8];
s1=z[0]+z[3]+z[6];
s2=z[1]+z[4]+z[7];
s3=z[2]+z[5]+z[8];
xz=z[2]+z[4]+z[6];
xy=z[0]+z[4]+z[8];
if(h1==3||h2==3||h3==3||s1==3||s2==3||s3==3||xz==3||xy==3)
printf("KiKi wins!\n");
else if(h1==-3||h2==-3||h3==-3||s1==-3||s2==-3||s3==-3||xz==-3||xy==-3)
printf("BoBo wins!\n");
else
printf("No winner!\n");
return 0;
}
int main()
{
int i,j,k,b,z[9]={0},h1=0,h2=0,h3=0,s1=0,s2=0,s3=0,xz=0,xy=0;
char a[9];
for(i=0;i<9;i++)
{
scanf(" %c",&a[i]);
if(a[i]=='K')
z[i]=1;
else if(a[i]=='B')
z[i]=-1;
else if(a[i]=='O')
z[i]=0;
}
h1=z[0]+z[1]+z[2];
h2=z[3]+z[4]+z[5];
h3=z[6]+z[7]+z[8];
s1=z[0]+z[3]+z[6];
s2=z[1]+z[4]+z[7];
s3=z[2]+z[5]+z[8];
xz=z[2]+z[4]+z[6];
xy=z[0]+z[4]+z[8];
if(h1==3||h2==3||h3==3||s1==3||s2==3||s3==3||xz==3||xy==3)
printf("KiKi wins!\n");
else if(h1==-3||h2==-3||h3==-3||s1==-3||s2==-3||s3==-3||xz==-3||xy==-3)
printf("BoBo wins!\n");
else
printf("No winner!\n");
return 0;
}
发表于 2022-02-16 17:20:11
回复(0)
#include <stdio.h>
char Jud(char ch[3][3]){
// 判定行
int j = 0;
for(j = 0; j < 3; j++){
if(ch[0][j] == ch[1][j] && ch[1][j] == ch[2][j]){
// 返回胜利者的棋子类型
return ch[0][j];
}
}
// 判定列
int i = 0;
for(i = 0; i < 3; i++){
if(ch[i][0] == ch[i][1] && ch[i][1] == ch[i][2]){
// 返回胜利者的棋子类型
return ch[i][0];
}
}
// 判定主对角线
if(ch[0][0] == ch[1][1] && ch[1][1] == ch[2][2]){
// 返回胜利者的棋子类型
return ch[1][1];
}
// 判定次对角线
if (ch[0][2] == ch[1][1] && ch[1][1] == ch[2][0]) {
// 返回胜利者的棋子类型
return ch[1][1];
}
// 否则目前没有人获胜，返回-1
return -1;
}
int main(){
char ch[3][3] = {0};
int i = 0;
int j = 0;
// 输入棋盘
for (i = 0; i < 3; i++) {
scanf("%c %c %c", &ch[i][0], &ch[i][1], &ch[i][2]);
// 每行输入完毕都要回车使得三个字符按%c %c %c格式导入scanf
// 所以每次输入完一行后，将剩余的\n清理
getchar();
}
// 判定
char ret = Jud(ch);
if ('K' == ret) {
printf("KiKi wins!\n");
}
else if ('B' == ret) {
printf("BoBo wins!\n");
}
else {
printf("No winner!\n");
}
return 0;
}
char Jud(char ch[3][3]){
// 判定行
int j = 0;
for(j = 0; j < 3; j++){
if(ch[0][j] == ch[1][j] && ch[1][j] == ch[2][j]){
// 返回胜利者的棋子类型
return ch[0][j];
}
}
// 判定列
int i = 0;
for(i = 0; i < 3; i++){
if(ch[i][0] == ch[i][1] && ch[i][1] == ch[i][2]){
// 返回胜利者的棋子类型
return ch[i][0];
}
}
// 判定主对角线
if(ch[0][0] == ch[1][1] && ch[1][1] == ch[2][2]){
// 返回胜利者的棋子类型
return ch[1][1];
}
// 判定次对角线
if (ch[0][2] == ch[1][1] && ch[1][1] == ch[2][0]) {
// 返回胜利者的棋子类型
return ch[1][1];
}
// 否则目前没有人获胜，返回-1
return -1;
}
int main(){
char ch[3][3] = {0};
int i = 0;
int j = 0;
// 输入棋盘
for (i = 0; i < 3; i++) {
scanf("%c %c %c", &ch[i][0], &ch[i][1], &ch[i][2]);
// 每行输入完毕都要回车使得三个字符按%c %c %c格式导入scanf
// 所以每次输入完一行后，将剩余的\n清理
getchar();
}
// 判定
char ret = Jud(ch);
if ('K' == ret) {
printf("KiKi wins!\n");
}
else if ('B' == ret) {
printf("BoBo wins!\n");
}
else {
printf("No winner!\n");
}
return 0;
}
发表于 2022-01-04 11:48:47
回复(0)
问题信息
通过挑战的用户
查看代码-
2023-03-08 11:56:27
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2022-10-20 10:29:25
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2022-09-15 22:11:36 -
2022-09-15 17:24:48
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