左连接下一天 还有首次登录时间 然后计算代码如下 with t1 as( select l1.*, l2.user_id uid2, min(l1.date) over(partition by l1.user_id) as mdate from login l1 left join login l2 on datediff(l2.date, l1.date) = 1 and l1.user_id = l2.user_id ) select date, ifnull(round(count(distinct (case when d...