如何实现顺时针旋转矩阵？ package chapter_8_arrayandmatrix; public class Problem_01_PrintMatrixSpiralOrder { public static void spiralOrderPrint(int[][] matrix) { int tR = 0; int tC = 0; int dR = matrix.length - 1; int dC = matrix[0].length - 1; while (tR <= dR && tC <= dC) { printEdge(matrix, tR++, tC++, dR--, dC--); } } public static void printEdge(int[][] m, int tR, int tC, int dR, int dC) { if (tR == dR) { // 子矩阵只有一行时 for (int i = tC; i <= dC; i++) { System.out.print(m[tR][i] + " "); } } else if (tC == dC) { // 子矩阵只有一列时 for (int i = tR; i <= dR; i++) { System.out.print(m[i][tC] + " "); } } else { // 一般情况 int curC = tC; int curR = tR; while (curC != dC) { System.out.print(m[tR][curC] + " "); curC++; } while (curR != dR) { System.out.print(m[curR][dC] + " "); curR++; } while (curC != tC) { System.out.print(m[dR][curC] + " "); curC--; } while (curR != tR) { System.out.print(m[curR][tC] + " "); curR--; } } } public static void main(String[] args) { int[][] matrix = { { 1, 2, 3, 4 }, { 5, 6, 7, 8 }, { 9, 10, 11, 12 }, { 13, 14, 15, 16 } }; spiralOrderPrint(matrix); } }