题解 | KiKi求质数个数
KiKi求质数个数
https://www.nowcoder.com/practice/d3a404ee0f8d41f98bf4707035d91086
p=0
for i in range(100,1000):
s=0
for j in [2,3,5,7,11,13,17,19,23,29,31,37,41,43,47,51]:
if i%j!=0:
s+=1
if s==16:
p+=1
print(p)
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