题解 | 特殊的科学计数法

#include <stdio.h>
#include <string.h>
int main() 
{
    char n[100001] = "\0";
    scanf("%s", n); 
    char a = n[0];
    char b = n[1];
    int c = (int)strlen(n) - 1;
    char d = n[2];
    if (d > '4')
    {
        if (b != '9')
           b += 1;
        else
         {
            if (a != '9')
            {
                b = '0';
                a += 1;
            }
            else 
            {
                
                    b = '0';
                    a = '1';
                    c++;
            }
         }
    }    
    printf("%c.%c*10^%d", a, b, c);
    return 0;
}