题解 | 计算日期到天数转换

#include <stdio.h>

int main() {
    int year, month, day;
    while (scanf("%d %d %d", &year, &month, &day) != EOF) { // 注意 while 处理多个 case
        // 64 位输出请用 printf("%lld") to 
        int m[13] = {0,31,28,31,30,31,30,31,31,30,31,30,31};
        if(((year%4==0)||(year%400==0))&&(year%100!=0)){
            m[2] = 29;
        }
        int days = 0;
        for(int i = 0; i < month; i++){
            days += m[i];
        }
        days += day;
        printf("%d",days);
    }
    return 0;
}