题解 | 凯撒加密
凯撒加密
https://www.nowcoder.com/practice/006b7917d3784371a43cfbae01a9313d
#include <iostream>
using namespace std;
#include<string>
int main() {
int n;
string s;
cin>>n>>s;
n=n%26;
for(int i=0;i<s.size();i++){
if(s[i]+n>'z'){
s[i]= 'a'+ n-('z'-s[i]+1);
}
else{
s[i]+=n;
}
}
cout<<s;
}
// 64 位输出请用 printf("%lld")
