题解 | 单组_spj判断数组之和
单组_spj判断数组之和
https://www.nowcoder.com/practice/da783089da3b4a3188d240e1b7ac4b23
# 读取n和m
n, m = map(int, input().split())
# 基础数组：n个1
arr = [1] * n
# 计算差值
diff = m - n
# 把差值全部加到最后一个元素上
arr[-1] += diff
# 输出数组（按ACM题要求，元素用空格分隔）
print(' '.join(map(str, arr)))
