题解 | 确定最佳顾客的另一种方式（二）
确定最佳顾客的另一种方式（二）
https://www.nowcoder.com/practice/b5766f970ae64ac7944f37f5b47107aa
select
c.cust_name,
sum(oo.item_price * oo.quantity) as total_price
from
Orders AS o
inner join Customers as c on o.cust_id = c.cust_id
inner join OrderItems as oo on o.order_num = oo.order_num
group by
c.cust_name
having total_price >= 1000
如果有两张以上的多表查询可以使用：
select....
from....
where.....；
这样的结构，可以少写两个inner join。
