题解 | 牛牛的西格玛
牛牛的西格玛
https://www.nowcoder.com/practice/c6b750ee8853484f8dbf14b9531b501f
#include <stdio.h>
int plus(int n)
{
if(n <= 0)
return 0;
else
return (n + plus(n - 1));
}
int main() {
int n;
scanf("%d",&n);
printf("%d",plus(n));
return 0;
}
请叫我递归哥！
查看7道真题和解析