题解 | 矩阵转置
矩阵转置
https://www.nowcoder.com/practice/351b3d03e410496ab5a407b7ca3fd841
#include <stdio.h>
int main() {
int n, m;
scanf("%d %d", &n, &m);
int arr[10][10] = {0};
int i = 0;
int j = 0;
for (i = 0; i < n; i++) {
for (j = 0; j < m; j++) {
scanf("%d",& arr[i][j]);
}
}
for (i = 0; i < m; i++) {
for (j = 0; j < n; j++) {
printf("%d ", arr[j][i]);
}
printf("\n");
}
return 0;
}
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